Answer:
(a) 1s² 2s² 2p⁶ 3s² 3p⁴
(b) 1s² 2s² 2p⁶ 3s² 3p⁵
(c) sp³
(d) No valence orbital remains unhybridized.
Explanation:
<em>Consider the SCl₂ molecule. </em>
<em>(a) What is the electron configuration of an isolated S atom? </em>
S has 16 electrons. Its electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁴.
<em>(b) What is the electron configuration of an isolated Cl atom? </em>
Cl has 17 electrons. Its electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁵.
<em>(c) What hybrid orbitals should be constructed on the S atom to make the S-Cl bonds in SCl₂? </em>
SCl₂ has a tetrahedral electronic geometry. Therefore, the orbital 3s hybridizes with the 3 orbitals 3 p to form 4 hybrid orbital sp³.
<em>(d) What valence orbitals, if any, remain unhybridized on the S atom in SCl₂?</em>
No valence orbital remains unhybridized.
I would say chemical but I’m not 100% sure might wanna get a second opinion
Answer:
A
B
C
Explanation:
A B and C are heterogeneous because they don’t have all the same components throughout. D is homogeneous because kool aid dissolves into the water.
Answer:
Explanation:
Expression for capillary rise is as follows
h = 2T / ρ g r where T is surface tension , ρ is density of liquid and r is radius of capillary tube.
T = .032 J m⁻²
ρ = .71 g / cm³
= 7100 kg / m³
r = .1 x 10⁻³ m = 10⁻⁴ m
h = 2 x .032 / (7100 x 9.8 x 10⁻⁴ )
h = .0092 m
= 9.2 mm .
I hope you understand my working:
1) Finding the mol of NH3 to find the mol of (NH4)2SO4 (ammonium sulfate)
2) Mr of (NH4)2SO4
3) Theoretical yield: The actual grams of (NH4)2SO4 produced when reacting 0.514 mol of NH3 to 0.514 mol H2SO4
4) Using formula of (given grams)/(theoretical grams or actual grams) * 100 = 73%
5) Basic algebra
