X = 13
( x + 4) / 51 = (2x - 7) / 57
585 = 45x
585/45 = 45x/45
x = 13
Answer:
About 42%
Step-by-step explanation:
Triple t ⇒ 3t
add the result to u ⇒ 3t + u
multiply what you have by v ⇒ (3t + u)v
Since it is instructed not to simplify, we perform the distributive property of multiplication.
(3t + u)v = 3tv + uv
Answer:
25.5 mph
Step-by-step explanation:
So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed
So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15
y=2(0.25)+40
y=0.5+40
y=40.5
So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed
40.5 - 15 = 25.5
To find the number of zeros in the quadratic equation we factorize it as follows:
f(x)=x²+6x+18
solving using completing square methods we obtain:
x^2+6x=-18
c=(b/2a)^2=9
thus
x²+6x+9=-18+8
x²+6x+9=-9
(x+3)²=-9
hence
x=-3+/-3i
the roots are:
x=-3+3i or x=-3-3i
