Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
Answer:
Step-by-step explanation:
Recall the intercept form of the line
x/a + y/b = 1
has intercepts at (1,0) and (0,b)
#1. Divide by 24 to get x/8 + y/-6 = 1
The intercepts are at (8,0) and (0,-6)
#2 Divide by 12
x/-2 + y/4 = 1
Answer:
45/51
Step-by-step explanation:
SOH CAH TOA
Sin x = Opposite/hyp
Cos x = Adjacent/hyp
Tan x = Opposite/Adjac
Here we're looking for Sin R, so we want to find opposite side over the hypotenuse.
Thus, 
