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vladimir1956 [14]
2 years ago
6

if you transfer equal amounts of geat to 1kg of water and 1kg of cooper, which will change tempature more

Physics
1 answer:
Angelina_Jolie [31]2 years ago
4 0

If you transfer equal amounts of geat to 1kg of water and 1kg of cooper, the temperature of the cooper will change more . . . it'll get more degrees warmer than the water will.

That's because the specific geat of water is greater than the specific geat of cooper.

(This just means it takes more geat to warm some mass of water by some amount than it takes to warm the same mass of cooper by the same amount.)  

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What is the correct equation for calculating the average atomic mass for 3 isotopes? (pls be 100%of your answer pls no guessing)
mariarad [96]

<u>Answer:</u>

<em>The correct equation for measuring the average microscopic weight  for 3 isotopes is multiply the rate of abundance by each weight and add them.</em>

<u>Explanation:</u>

To calculate the average microscopic mass of element using weights and relative abundance we have to follow the following steps.

  • Take the correct weight of each isotope (that will be in decimal form)
  • Multiply the weight of each isotope by its abundance
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<em>This gives the required  average microscopic weight of the three isotopes.</em>

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2 years ago
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3 years ago
A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in t
Vladimir [108]

Answer:

The index of refraction of the glass is 1.3

Explanation:

Given data:

i = incident angle = 50°

r = refracted angle = 36.1°

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n=\frac{1*sini}{sinr} =\frac{1*sin50}{sin36.1} =1.3

4 0
3 years ago
When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo
Natali5045456 [20]

Answer:

46.4 s

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5 minutes = 60 * 5 = 300 seconds

Let g = 9.8 m/s2. And \theta be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim .  Both of their motions are subjected to parallel component of the gravitational acceleration gsin\theta

Rob equation of motion can be modeled as s = a_Rt_R^2/2 = a300^2/2 = 45000a[/tex]

Jim equation of motion is s = a_Jt_J^2/2 = (3a/4)t_J^2/2 = 3at_J^2/8

As both of them cover the same distance

45000a = 3at_J^2/8

t_J^2 = 45000*8/3 = 120000

t_J = \sqrt{120000} = 346.4 s

So Jim should start 346.4 – 300 = 46.4 seconds earlier than Rob in other to reach the end at the same time

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3 years ago
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Norma-Jean [14]

Answer:

aw why? are you deleting the app for school?

6 0
2 years ago
Read 2 more answers
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