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MA_775_DIABLO [31]
2 years ago
8

A car starting from rest accelerated at a rate of 0 .5 m/s up to 2 km what would be the final velocity of the car and how much t

ime would it take to cover 1.6​​
Physics
2 answers:
sertanlavr [38]2 years ago
7 0
  • Initial velocity=u=0m/s
  • Acceleration=a=0.5m/s^2
  • Distance=s=1.6m
  • Final velocity=v=?

Using third equation of kinematics

\\ \rm\longmapsto v^2=u^2+2as

\\ \rm\longmapsto v^2=0^2+2(0.5)(1.6)

\\ \rm\longmapsto v^2=1.6

\\ \rm\longmapsto v=\sqrt{1.6}

\\ \rm\longmapsto v=0.4m/s

Now using 1st equation of motion

\\ \rm\longmapsto v=u+at

\\ \rm\longmapsto t=v-u/a

\\ \rm\longmapsto t=\dfrac{0.4-0}{0.5}

\\ \rm\longmapsto t=\dfrac{4}{5}

\\ \rm\longmapsto t=0.8s

Julli [10]2 years ago
4 0

From equation of motion v^2 = u^2 +2aS

Hence, the final velocity is 40 m/s.

<em><u>hope </u></em><em><u>it's </u></em><em><u>help </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>! </u></em>

<em><u>#</u></em><em><u>rishu</u></em>

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