Answer:
proton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleusproton and electrons orbit close together around a center nucleus
Explanation:
Answer: B
Explanation:
The top number is its atomic number, also known as the number of protons in the atom.
The bottom number is the atomic mass, which is the sum of the number of protons and neutrons.
The answer is b I’m oretty sure
Answer:
The correct option is that both the ends will remain neutral.
Explanation:
As the rod is grounded all of the prolonged charge will be converted to ground so the overall charge on the rod in absence of the charged ball will be equal to zero.Such that the both ends will not bear any charge.
Answer:
9:2
Explanation:
Series connection
Rt = R1 + R2 = 2 + 4 = 6 ohms
Parallel connection
1/Rt = 1/R1 + 1/R2 = 1/2 + 1/4 = (2+1)/4 = 3/4
1/Rt = 3/4
===> Rt = 4/3 = 1.33 ohms
ratio of series to parallel
6÷4/3 = 6×3/4 = 9:2