How do you do this question? Please include free body diagrams and clear explanation, so I can understand.
1 answer:
Explanation:
Draw a free body diagram for each disc.
Disc A has three forces acting on it: 86.5 N up, T₁ down, and Wa down.
∑F = ma
86.5 N − T₁ − Wa = 0
Wa = 86.5 N − T₁
ma × 9.8 m/s² = 86.5 N − 55.6 N
ma = 3.2 kg
Disc B has three forces acting on it: T₁ up, T₂ down, and Wb down.
∑F = ma
T₁ − T₂ − Wb = 0
Wb = T₁ − T₂
mb × 9.8 m/s² = 55.6 N − 36.5 N
mb = 1.9 kg
Disc C has three forces acting on it: T₂ up, T₃ down, and Wc down.
∑F = ma
T₂ − T₃ − Wc = 0
Wc = T₂ − T₃
mc × 9.8 m/s² = 36.5 N − 9.6 N
mc = 2.7 kg
Disc D has two forces acting on it: T₃ up and Wd down.
∑F = ma
T₃ − Wd = 0
Wd = T₃
md × 9.8 m/s² = 9.6 N
md = 0.98 kg
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Answer:
Average speed is 24 m/min
in another unit is is 0.4 m/s
Explanation:
As we know that the average speed is the ratio of total distance covered and total time
so here we know that total distance moved by the baptist is
total time taken by it is given as
so average speed is given as
now we have to find the speed in m/s unit also
so we have
Since the Units presented are not in the International System we will proceed to convert them. We know that,
So the speed in SI would be
The change in frequency when the wave is reflected is
Or we can rearrange the equation as
f' = Apparent frequency
f = Original Frequency
c = Speed of light
Replacing,
Since the waves are reflected, hence the change in frequency at the gun is equal to twice the change in frequency
Therefore the increase in frequency is 2979.63Hz