Answer:
Explanation:
Let the critical angle be C .
sinC = 1 / μ where μ is index of refraction .
sinC = 1 /1.2
= .833
C = 56°
Then angle of refraction r = 90 - 56 = 34 ( see the image in attached file )
sin i / sinr = 1.2 , i is angle of incidence
sini = 1.2 x sinr = 1.2 x sin 34 = .67
i = 42°.
115.94g of O₂ are produced by 250g of Ca(ClO₃)₂
<u>Explanation:</u>
Ca(ClO₃)₂ -->CaCl₂ + 3O₂
One mole of calcium chlorate give three moles of oxygen.
Molar mass of calcium chlorate is
40+(35.5+16*3)*2 = 207g/mol
Molar mass of Oxygen = 32g
1 mole of calcium chlorate decomposes to form 3 moles of oxygen.
So,
207g of Ca(ClO₃)₂ produces 3 X 32g of O₂
250g of Ca(ClO₃)₂ will produce =
= 115.94g of O₂
Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂