How much gravitational potential energy does the block have
when it gets to the top of the ramp ?
(weight) x (height) = (15 N) x (0.2 m) = 3 Joules .
If there were no friction, you would only need to do 3 Joules of work
to lift the block from the bottom to the top.
But the question says you actually have to do 4 Joules of work
to get the job done.
Friction stole one of your Joules along the way.
Choice-4 is not the correct one.
Choice-1 is the correct one.
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Notice that the mass of the block is NOT 15 kg , and you
don't have to worry about gravity to answer this question.
The formula for potential energy is (m)·(g)·(h) .
But (m·g) is just the WEIGHT, and the formula
is actually (weight)·(height).
The question GIVES us the weight of the block . . . 15 N .
So the potential energy at the top is just (15N)·(0.2m) = 3 Joules.
Answer:
the relationship between the voltage and the resistance is linear,
light bulb. a lot of energy to be in the system in the form of electromagnetic radiation and heat, this loss of energy is the cause of the loss of the linearity of ohm's law.
Explanation:
When you study ohm's law
V = i R
You observe that the relationship between the voltage and the resistance is linear, so the law of compliance, when you used a resistor, the law was fulfilled, the resistor did not heat up significantly.
When you used the bulb, the resistance values is small, so the passing current is high and the filament heats up significantly, to the point of emitting light, so the resistance can linearity. This is because the collisions between the electrons and the atoms is very frequent creating excitations and de-excitations that cause a lot of energy to be in the system in the form of electromagnetic radiation and heat, this loss of energy is the cause of the loss of the linearity of ohm's law.
Answer:187500m
Explanation:
frequency=1600kHz
Velocity=3x10^8 m/s
Wavelength=velocity ➗ frequency
Wavelength=(3x10^8) ➗ 1600
Wavelength=187500m
Answer:
independent variables are variables in mathematical modeling, statistical modeling and experimental science
Answer:
The diameter of the moon's image is 0.31 cm.
Explanation:
Given that,
Focal length = 34.3 cm
Diameter of the moon
Mean distance from the earth
At that distance the object is assumes to be at infinity. hence the image will be formed at a distance equal to focal length
So, the image distance is 34.3 cm.
We need to calculate the diameter of the moon's image
Using formula of magnification
Hence, The diameter of the moon's image is 0.31 cm.