Answer:
<em>The florist should make 9 Easter bouquet and 6 Spring bouquet to maximize the profit.</em>
Step-by-step explanation:
Suppose, the number of the Easter bouquet is and the number of Spring bouquet is .
The Easter bouquet requires 10 jonquils and 20 daisies, and the Spring bouquet requires 5 jonquils and 20 daisies.
So, the total number of jonquils required
and the total number of daisies required
Given that, there are total 120 jonquils and 300 daisies are available. So, the constraints will be........
<em>(As the number of each type of bouquet can't be negative)</em>
Now, each Easter bouquet produces a profit of $1.50 and each Spring bouquet produces a profit of $1. So, t<u>he profit function will be</u>:
If we graph the constraints now, then the <u>vertices of the common shaded region</u> are: and
For (0, 0) ⇒
For (12, 0) ⇒
For (9, 6) ⇒
For (0, 15) ⇒
So, <u>the profit will be maximum when</u> and
Thus, the florist should make 9 Easter bouquet and 6 Spring bouquet to maximize the profit.