Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)



so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
Answer:
5(2x - 1)
Step-by-step explanation:
Given
2(x - 6) + 4(2x + 1) + 3 ← distribute both parenthesis
= 2x - 12 + 8x + 4 + 3 ← collect like terms
= (2x + 8x) + (- 12 + 4 + 3)
= 10x + (- 5)
= 10x - 5 ← factor out 5 from each term
= 5(2x - 1) ← in factored form
The negitives are far from the 0 so its less than the non negitives
Answer:
1 hour 9 minutes
Step-by-step explanation:
Answer:
0.23
Step-by-step explanation:
you divide the percent by 100 I think