Question

A person who is 180 cm tall and weighs 750 newtons is driving a car at a speed of 90 kilometers per hour over a distance of 80 kilometers. The outside air temperature is 30^\circ∘C and has a density of 1.2 kilograms per cubic meter (kg/m3). Convert all of the values given in this example from SI units to U.S. Customary units.

Answer 1

Answer:

5.90551 ft

168.6151 lbf

55.92354 mph

49.70981 mi

0.07491 lb/ft³

Explanation:

Convert cm to ft

$1\ cm=\dfrac{1}{30.48}\ ft$

$180\ cm=180\times \dfrac{1}{30.48}\ ft=5.90551\ ft$

180 cm = 5.90551 ft

Convert N to lbf

$1\ N=\dfrac{1}{4.448}\ lbf$

$750\ N=750\times \dfrac{1}{4.448}\ lbf=168.6151\ lbf$

750 N = 168.6151 lbf

Convert kmph to mph

$1\ kmph=\dfrac{1}{1.60934}\ mph$

$90\ kmph=90\times \dfrac{1}{1.60934}=55.92354\ mph$

90 kmph = 55.92354 mph

Convert km to mi

$1\ km=\dfrac{1}{1.60934}\ mi$

$80\ km=80\times \dfrac{1}{1.60934}=49.70981\ mi$

80 km = 49.70981 mi

Convert °C to °F

$^{\circ}C=(^{\circ}C\times \dfrac{9}{5})+32$

$30^{\circ}C=(30^{\circ}C\times \dfrac{9}{5})+32=86^{\circ}F$

30°C = 86°F

Convert kg/m³ to lb/ft³

$1\ kg/m^3=\dfrac{2.20462}{3.28084^3}\ lb/ft^3$

$1.2\ kg/m^3=1.2\times \dfrac{2.20462}{3.28084^3}=0.07491\ lb/ft^3$

1.2 kg/m³ = 0.07491 lb/ft³