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Sauron [17]
3 years ago
12

I'll Vote Brainliest

Physics
1 answer:
aliina [53]3 years ago
8 0
B) only in animal cells


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Disk A, with a mass of 2.0 kg and a radius of 60 cm , rotates clockwise about a frictionless vertical axle at 20 rev/s . Disk B,
Vladimir79 [104]

Answer:

Explanation:

  • let m1 = 2 kg
  • r1 = 60 cm = 0.6 m
  • w1 = -20 rev/s (clockwise)

I1 = 0.5 x m1 x r1²

= 0.5 x 2 x 0.6²

= 0.36 kg.m²

m2 = 2 kg

r2 = 40 cm = 0.4 m

w2 = 20 rev/s (counter clockwise)

I2 = 0.5 x m2 x r2²

= 0.5 x 2 x 0.4²

= 0.16 kg.m²

let wf be the final angular velocity of the two disks.

Applying conservation of angular momentum ;

(I1 + I2) x wf = I1 x w1 + I2 x w2

wf = (I1 x w1 + I2 x w2) / (I1 + I2)

= (0.36 x (-20) + 0.16 x 20 )/(0.36 + 0.16)

= -7.69rev/s

The negative sign indicates the disks rotate clockwise direction.

6 0
3 years ago
A projectile is fired with a velocity of 320 ms at an angle of 30 degree to a horizontal.1 Find the time to reach the maximum he
dedylja [7]

(a) The time taken for the projectile to reach the maximum height is 32.65 s.

(b) The horizontal range of the projectile is 9,049.1 m.

The given parameters:

  • Initial velocity of the projectile, u = 320 m/s
  • Angle of projection, = 30 degrees

The time taken for the projectile to reach the maximum height is calculated as follows;

v_f = u- gt\\\\0 = 320 - 9.8t\\\\9.8t = 320\\\\t = \frac{320}{9.8} \\\\t = 32.65 \ s

The horizontal range of the projectile is calculated as follows;

R = \frac{u^2 sin(2\theta)}{g} \\\\R = \frac{320^2 \times sin(2\times 30)}{9.8} \\\\R = 9,049.1 \ m

Learn more about horizontal range here: brainly.com/question/12870645

6 0
3 years ago
As you run toward a source of sound, you perceive the frequency of that sound to
Nata [24]

As you run toward a source of sound, you perceive the frequency of that sound to decrease.

<u>Explanation:</u>

Doppler's effect is a principle used to describe the frequency and the intensity of sound and wavelengths of a source and observer with the two possibilities.

(i) Stationary sound source and moving observer.

(ii) Moving sound source and a stationary observer. It is a relative motion.

Consider when the observer is moving towards a source, the frequency of the sound will be higher and when moving away from the source, the frequency will decrease.

5 0
4 years ago
Read 2 more answers
A sailboat starts from rest and accelerates at a rate of 0.21 m/s^2 over a distance of 280 m. find the magnitude of the boat's f
sasho [114]

We use the kinematic equations,

v=u+at                                          (A)

S= ut + \frac{1}{2} at^2                  (B)

Here, u is initial velocity, v is final velocity, a is acceleration and t is time.

Given,  u=0, a=0.21 \ m/s^2 and s= 280 m.

Substituting these values in equation (B), we get

280 \ m = 0 +\frac{1}{2} (0.21 m/s^2) t^2 \\\\ t^2 = \frac{280 \times 2}{0.21 } \\\\ t= 51.63 \ s.

Therefore from equation (A),

v = 0 + (0.21) \times (51.63 s)= 10.84 \ m/s

Thus, the magnitude of the boat's final velocity is 10.84 m/s and the time taken by boat to travel the distance 280 m is 51.63 s



8 0
3 years ago
WILL GIVE BRAINLIEST!! Part 1: Other than distance from the sun, which factor affects the temperature of a planet?
Svet_ta [14]
The thickness of the ozone layer (for earth) and the atmosphere.
Mercury is the closest planet to the sun but it isn’t the hottest because it has no atmosphere. Although Venus is the second planet from the sun, it is the hottest because of it’s thick atmosphere and the clouds that trap heat in.
8 0
4 years ago
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