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exis [7]
2 years ago
10

THREE-DIMENSIONAL THINKING

Physics
1 answer:
ANEK [815]2 years ago
8 0

The presence of potential energy  between particles supports the shape of a heating curve.

<h2>Potential energy and heating curve</h2>

The existence of potential energy  between particles supports the shape of a heating curve because potential energy causes the heating curve flat as well as in curve form. The heating curves show how the temperature changes as a substance is heated up.

The potential energy of the molecules will increase anytime energy is being supplied to the system but the temperature is not increasing so when the heating curve go flat it means there is potential energy so we can conclude that the existence of potential energy  between particles supports the shape of a heating curve.

Learn more about heating curve here: brainly.com/question/11991469

Learn more: brainly.com/question/26153233

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on a standard position vs time graph, the distance between two points on the horizontal axis represents the time interval, and t
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Answer: true

Explanation: I got the question and guessed true and it was right

3 0
2 years ago
The ratio of the lift force L to the drag force D for the simple airfoil is L/D = 10. If the lift force on a short section of th
Yuri [45]

Answer:

R=64.32\ lb\\\\\theta=84.3\°

Explanation:

Given:

Ratio of lift force to drag force is, \frac{L}{D}=10

Lift force on a short section is, L=64\ lb

Magnitude of resultant, R= ?

The angle of 'R' with the horizontal is, \theta=?

We know that, lift force and drag are at right angles to each other. So, the resultant can be computed using Pythagoras theorem.

For calculating 'R', we first compute drag force 'D'.

As per question:

\frac{L}{D}=10\\\\D=\frac{L}{10}=\frac{64\ lb}{10}=6.4\ lb

Now, the magnitude of resultant 'R' is given as:

R=\sqrt{L^2+D^2}

Plug in the given values and solve for 'R'. This gives,

R=\sqrt{64^2+6.4^2}\\\\R=\sqrt{4096+40.96}\\\\R=\sqrt{4136.96}=64.32\ lb

Therefore, the magnitude of the resultant force 'R' is 64.32 lb.

Now, the angle \theta is given as the arctan of the ratio of the lift and drag force.

Therefore,

\theta=\tan^{-1}(L/D)\\\\\theta=\tan^{-1}(10)\\\\\theta=84.3\°

Therefore, the angle made with the horizontal is 84.3°.

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3 0
2 years ago
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Ede4ka [16]

Answer:

OT

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During practice it is very important to use protective gears or equipments because without them, injuries and accidents are liable to occur.

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The strength of the force of gravity depends on
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The masses of the objects and how much distance there is between them

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