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3 years ago

What is the square root of 36x^4

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

He’s right I’ve done the math myself as well

marissa [1.9K]3 years ago

6 0

What is the square root of 36x^4?

√36x^4 =

6x²

(√36=6 and √x^4 = x²)

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Use the slider to change the value of b. Which statement is true? If the value of b is increased from 0, the graph moves up. If

Alex

Answer: If the value of b is increased from 0, the graph moves up.

Step-by-step explanation:

I got it right.

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3 years ago

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Calculate 3217. km + 13.1 km + 1.30 km. round off if necessary to apply the rule of significant figures for addition and subtrac

QveST [7]

3217 + 13.1 + 1.3 can also be written as

3217.0
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3 years ago

4x2 + 8x - 7 - (3x2 - X+9)

Andreas93 [3]

Answer:

Step-by-step explanation:

$4 {x}^{2} + 8x - 7 - (3 {x}^{2} - x + 9)$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression:

$4 {x}^{2} + 8x - 7 - 3 {x}^{2} + x - 9$

Collect like terms

$4 {x}^{2} - 3 {x}^{2} + 8x + x - 7 - 9$

${x}^{2} + 9x - 7 - 9$

Calculate

${x}^{2} + 9x - 16$

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3 years ago

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Is x=5 the solution to the following equation? Show your work with the substitution property

guapka [62]

Answer:

yes

Step-by-step explanation:

2x-4=6

Let x = 5

2*5 - 4 = 6

10 -4 =6

6 = 6

Since this is true, x=5 is a solution to the equation

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3 years ago

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Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have changed the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

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2 years ago