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Zinaida [17]
3 years ago
14

if the following line are parallel peroendicular coinciding or intersectining but not perpendicular ????

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:In elementary geometry, the property of being perpendicular (perpendicularity) is the relationship between two lines which meet at a right angle (90 degrees). The property extends to other related geometric objects. A line is said to be perpendicular to another line if the two lines intersect at a right angle. Explicitly, a first line is perpendicular to a second line if (1) the two lines meet; and (2) at the point of intersection the straight angle on one side of the first line is cut by the second line into two congruent angles.

Step-by-step explanation:

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The longer side is 36 and the shorter side is 24
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Which choice describes the value of m when -5(m + 1) ≤ 23?
snow_tiger [21]

Answer:

Number 1

Step-by-step explanation:

-5(m + 1) ≤ 23

Distribute

-5m - 5 ≤ 23

-5m ≤ 23 + 5

-5m ≤ 28

-m ≤ 28/5

Since we divide by a negative the ≤ flips to ≥

m ≥ -28/5

Hope this helps :3

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Determine the approximate value of x.
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Answer:

 C.    6.736

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Solve the quadratic equation by using a graphic approach. Round your answer to the hundredths place.
den301095 [7]

Answer:

x = 3.24, x = -1.24

Step-by-step explanation:

The standard form for a quadratic equation is ax^2+bx+c=0. For your equation a = 1, b = -2, c = -4. The quadratic formula you will be using is x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}.

Plug in a = 1, b = -2, and c = -4 into the formula.

=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

We'll do the top part first:

\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}

Apply rule - (-a) = a

=\sqrt{\left(-2\right)^2+4\cdot \:1\cdot \:4}

Apply exponent rule (-a)^{n} =a^n if n is even

(-2)^2=2^2

=\sqrt{2^2+4\cdot \:1\cdot \:4}

Multiply the numbers

=\sqrt{2^2+16}

2^2=4

=\sqrt{4+16}

Add

=\sqrt{20}

The prime factorization of 20 is 2^2*5

20 divides by 2. <em>20 = 10 * 2</em>

<em />=2*10<em />

10 divides by 2. <em>10 = 5 * 2</em>

<em />=2* \:2*5<em />

2 & 5 are prime numbers so you don't need to factor them anymore

=2*2*5

=2^2*5

=\sqrt{2^2\cdot \:5}

Apply radical rule \sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

=\sqrt{5}\sqrt{2^2}

Apply radical rule \sqrt[n]{a^{n} } =a; \sqrt{2^2} =2

=2\sqrt{5}

=\frac{-\left(-2\right)\pm \:2\sqrt{5}}{2\cdot \:1}

Because of the \pm you have to separate the solutions so that one is positive and the other is negative.

x=\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1},\:x=\frac{-\left(-2\right)-2\sqrt{5}}{2\cdot \:1}

Positive x:

\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1}

Apply rule -(-a)=a

=\frac{2+2\sqrt{5}}{2\cdot \:1}

Multiply

=\frac{2+2\sqrt{5}}{2}

Factor 2+2\sqrt{5} and rewrite it as =2\cdot \:1+2\sqrt{5}. Factor out 2 because it is the common term. =2\left(1+\sqrt{5}\right).

=\frac{2\left(1+\sqrt{5}\right)}{2}

Divide 2 by 2

x=1+\sqrt{5} or x=3.24 (You'll probably have to use a calculator for the square root of 5)

^Repeating the process of positive x for negative x in order to get x=1-\sqrt{5} or x=-1.24

4 0
3 years ago
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