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3 years ago

Find the slope of the line passing through the points (-2, -8) and (9,-8). slope:

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

6 0

<h3>Answer: 0</h3>

To get that answer, apply the slope formula

m = (y2 - y1)/(x2 - x1)

m = (-8 - (-8))/(9 - (-2))

m = (-8 + 8)/(9 + 2)

m = 0/11

m = 0

Any line with slope 0 is completely horizontal.

As a quick rule of thumb: if the y coordinates of the two points are the same, then the slope is 0 on this horizontal line.

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Help me with this pls

oksano4ka [1.4K]

Answer:

x=9

Step-by-step explanation:

dyyfjfjsjujsjsivjsjicuejie82iu3828i$>÷>$>$>×&$:

4 0

3 years ago

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The recursive function for a sequence is given below.

masya89 [10]

Answer:

f(5) = 3200

Step-by-step explanation:

Using the recursive formula to generate the terms, that is

f(2) = 2 × f(1) = 2 × 200 = 400

f(3) = 2 × f(2) = 2 × 400 = 800

f(4) = 2 × f(3) = 2 × 800 = 1600

f(5) = 2 × f(4) = 2 × 1600 = 3200

8 0

3 years ago

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Find the volume of a square pyramid with a base area of 18inch squared and the height of 4 inches

den301095 [7]

Vpyramid=1/3 times area of base times height
volume=1/3 times 18 square inches times 4in
volume=6 square inches times 4in
volume=24 cubic inches

the volume is 24 cubic inches

5 0

3 years ago

The volume of a cone is 16 pi cubic inches. Its height is 12 inches. What is the radius of the cone? 2 in. 4 in. 12 in. 16 in.

mart [117]

The radius of cone is 2 inches

Solution:

The volume of cone is given by formula:

$V = \frac{\pi r^2h}{3}$

Where,

"V" is the volume of cone

"r" and "h" are the radius and height of cone respectively

Given that, volume of a cone is 16 pi cubic inches

Its height is 12 inches

Therefore, we get,

V = $16 \pi$ cubic inches

h = 12 inches

r = ?

Substituting the values in formula, we get

$16 \pi = \frac{ \pi \times r^2 \times 12}{3}\\\\16 = 4r^2\\\\r^2 = 4\\\\r = \pm 2$

Since, radius cannot be negative, ignore r = -2

Thus radius of cone is 2 inches

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3 years ago

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PLEASE HELP WITH ALGEBRA AND SHOW WORK :) an explanation would be nice too because this topic confuses me :/

fgiga [73]

$f(t) = t^2 + 4t-14\\ f(t)=t^2+4t+4-18\\ f(t)=(t+2)^2-18$

$f(x)=(x-h)^2+k \Rightarrow \text{vertex}=(h,k)\\\\ f(t)=(t+2)^2-18 \Rightarrow \text{vertex}=(-2,-18)$

It's a minimum, becuase $a=1>0$ .

The axis of symmetry is $x=h$ . So, in this case, it's $x=-2$ .

6 0

3 years ago