To get the answer for this problem your going to have to show us the frequency table
3%
Answer:
Selling price with VAT {15%} = Rs 41400
S.P +15% of S.P =Rs 41400
S.P(1+15%)=Rs 41400
S.P=Rs 41400/1.15
Selling price without VAT =Rs 36000
Again
Discount = 10%
M.P =S.P+ Discount % of M.P
M.P-Discount% of M.P= S.P
M.P(1-Discount%)=Rs 36000
M.P(1-10%)=Rs 36000
M.P=Rs 36000/0.9
Marked Price = Rs 40,000
again
Discount =Discount % of M.P
=10% of 40000
=Rs 4,000
Again
Profit=20%
For 20% profit
Cost price = (S.P*100)/(100+profit%)
=(36000*100)/(100+20)
= Rs 30000
For 24% profit
selling price = (100+profit%)*C.P/100
=(100+24)*30000/100
=Rs 37200
Again
Discount = 40000–37200 = Rs2800
Discount % = discount/M.P*100%
=2,800/40,000* 100 = 7%
Finally
Discount percent to be reduced =10%–7%= 3%
Answer:
490
Step-by-step explanation:
d(x)=700-7(30)
7x 30=210
700-210=490
therefore,
r(x)=490
Answer:
student ticket = $11
(adult ticket = $15)
Step-by-step explanation:
Let a = price of adult ticket
Let s = price of student ticket
Given:
- On the first night she sold 12 adult tickets and 11 student tickets for $301 dollars
⇒ 12a + 11s = 301
Given:
- On the second night she made $134 selling 6 adult tickets and 4 student tickets
⇒ 6a + 4s = 134
Multiply 6a + 4s + 134 by 2 then subtract from 12a + 11s = 301 to eliminate a:
⇒ (6a + 4s = 134) × 2: 12a + 8s = 268
12a + 11s = 301
- (12a + 8s = 268)
--------------------------
3s = 33
⇒ s = 33 ÷ 3 = 11
Substitute found value of s into one of the equations and solve for a:
⇒ 12a + 11(11) = 301
⇒ 12a + 121 = 301
⇒ 12a = 180
⇒ a = 15
Therefore, the price of an adult ticket is $15 and the price of a student ticket is $11
