Answer:
<u><em>Tube A will turn red the fastest. </em></u>
Explanation:
- Tube A will turn red fastest because Elodea plants will take up the white light and carry out photosynthesis.
- In tube B, the red colour will not be generated fastly because plants do not use green light. Usually, the green light is just reflected by the plants and it is not absorbed.
- In tube C, no photosynthesis will be able to occur because due to the wrapped aluminium foil the plants could not receive any light for photosynthesis.
Phagocytic response is considered the most effective host defenses in combating S. aureus infection.
<h3>What is phagocytic response?</h3>
Phagocytosis is a type of cell response that plays a key role in the course of an immune response as well as in the remodeling of tissues and the healing of wounds. Professional phagocytes are specialized cells that can carry out this task quite effectively.
<h3>What is S. aureus infection?</h3>
It has long been known that S. aureus is one of the most significant germs that harm humans. It is the main contributor to skin and soft tissue infections such cellulitis, furuncles, and abscesses (boils). Boils are the most typical staph infection form. This is a pus-filled pocket that forms in an oil gland or hair follicle. Typically, the skin around the infected area turns red and swells. To treat staph infections, doctors frequently administer cefazolin, nafcillin, oxacillin, vancomycin, daptomycin, and linezolid. Vancomycin may be necessary for staph infections that are severe. This is due to the fact that a large number of staph bacterium strains have developed resistance to other common antibiotics.
Thus from above conclusion we can say that phagocytic response is considered the most effective host defenses in combating S. aureus infection.
Learn more about the phagocytic response here:
brainly.com/question/28232491
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Lipids would be the answer
Answer:
There are 2 sex chromosomes – X and Y. Females have 22 autosomes and two X chromosomes, i.e., 22 + XX, while males have 22 autosomes and an X and Y chromosome each, i.e., 22 + XY. hope it helps.
basically 22
Explanation:
Answer:the item that has steps involved in glucose oxidation in an aerobic environment is ATP.
CH12O6 + 6O2 + 36Pi^-1 + 36ADP^3- + 35H^+ = 6CO2 + 36ATP^4- + 42H2O
Explanation:
Aerobic oxidation of glucose is coupled to the synthesis of as many as 36 molecules of ATP: Glycolysis, the initial stage of glucose metabolism, takes place in the cytosol and does not involve molecular O2. It produces a small amount of ATP and the three-carbon compound pyruvate.
