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DochEvi [55]
2 years ago
9

What is true of a molecule?

Chemistry
1 answer:
Zanzabum2 years ago
3 0

Answer:

Each atom of a molecular is the same yes it is right answer

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How many Grams would he present if 1 mole sample of sodium were collected?
Zigmanuir [339]
Mass = moles x Mr
So in this case the moles =1
And the Mr equals =11
So you would do - 11x1= 11grams
8 0
3 years ago
Cho 200 g dung dịch NaCl 0,5M tác dụng hết với 400 ml AgNO3. Sau phản ứng thu được kết tủa và dung dịch không màu
ivolga24 [154]

Answer:

Explanation:

a. NaCl+ AgNO3-----> NaNO3+ AgCl

b. Số mol của NaCl= 0,2*0,5= 0,1 (mol)

------> Số mol của kết tủa AgCl tạo thành= 0,1 mol (dựa vào phương trình hóa học)

-----> Khối lượng của kết tủa AgCl tạo thành= 0,1*143,5=14,35(g)

c. Số mol của AgNO3= số mol của NaCl= 0,1 (mol)

------> Nồng độ mol của dd AgNO3 đã tham gia phản ứng= \frac{0,1}{0,4}=0,25(M)

4 0
2 years ago
1. To begin, check that this question is shown: The tallest building in the world, the Burj Khalifa
zimovet [89]

Answer:

Explanation:

a. 82,000

b.Metric unit

5 0
1 year ago
A cylinder with a moveable piston contains 198 mL of nitrogen
lyudmila [28]

Answer: 195 mL

Explanation:

6 0
3 years ago
In a chemistry laboratory, a student filled a 10.0 L container with two (2) different gases. The
alexgriva [62]

Answer:

P_N=1.33atm\\\\P_O=0.67atm

P_T=2.00 atm

Explanation:

Hello.

In this case, the first step is to compute the moles of nitrogen and oxygen given their initial P, T and V conditions via the ideal gas equation:

n_{N}=\frac{P_{N}V_{N}}{RT} =\frac{2.00atm*24.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{N}=2.144molN\\\\n_{O}=\frac{P_{O}V_{O}}{RT} =\frac{2.00atm*12.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{O}=1.072molO

After that, since the total volume now, once the mixture is formed is the addition between the initial volumes (12.0 L + 24.0 L) is 36.0 L, the partial pressure of each gas turns out:

P_N=\frac{2.144mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_N=1.33atm\\\\P_O=\frac{1.072mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_O=0.67atm

Thus, the final total pressure is:

P_T= P_N+P_O=1.33atm+0.67atm\\\\P_T=2.00 atm

Best regards.

3 0
3 years ago
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