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3 years ago

CH3COOH mc015-1.jpg CH3COO– (aq) + H+(aq) What will happen to the chemical equilibrium of the solution if CH3COONa is added?

1 answer:

andrey2020 [161]3 years ago

7 0

The equilibrium will shift to the left or the backward reaction since addition of <span>CH3COONa will add more CH3COO- ions to the solution. The formation of reactants are promoted.</span>

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Calculating the Molecular Weight and Subunit Organization of a Protein From Its Metal Content The element molybdenum (atomic wei

Deffense [45]

Answer:

Dimer of two peptide chains with 1 mole of molybdenum metal each.

Explanation:

Percentage of molybdenum in protein = 0.08%

Molecular mass of nitrate reductase = 240,000 g

Mass of molybdenum = x

$0.08\%=\frac{x}{240,000 g}\times 100=192 g$

Moles of molybdenum = $\frac{192 g}{95.95 g/mol}=2.00 mol$

Each peptide chain of nitrate reductase contain 1 mole of molybdenum.

This means that nitrate reductase is composed of to two peptide chains. And in each peptide there is a single mole of molybdenum metal.

4 0

3 years ago

Consider the following genotype Yy Ss Hh

Ilya [14]

From: Yy Ss Hh 8 different gametes can be formed

5 Eye Color Genes = 243 genotypes
10 Eye Color Genes= 59049 genotypes
20 Eye Color Genes= 3,486,784,401 genotypes

This is further explained below.

<h3>What is a gamete?</h3>

Generally, Gametes are the cells of an organism that are responsible for reproduction. In certain contexts, they are also referred to as egg cells and sperm cells.

The popular word for female gametes is ova, whereas the common name for male gametes is sperm. Ovum and egg cells are other frequent names for female gametes.

Gametes are instances of haploid cells since they only contain a single copy of each chromosome. Haploid cells are described as having only one copy of each chromosome.

In conclusion, For 5 Eye Color Genes

3^n is implored hence

3^5=243 genotypes

Repeating said pattern e have

10 Eye Color Genes= 59049 genotypes
20 Eye Color Genes= 3,486,784,401 genotypes

Read more about gamete

brainly.com/question/2569962

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4. Consider the following genotype: Yy Ss Hh. We have now added the gene for height: Tall (H) or Short (h).

a. How many different gamete combinations can be produced?

b. Many traits (phenotypes), like eye color, are controlled by multiple genes. If eye color were controlled by the number of genes indicated below, how many possible genotype combinations would there be in the following scenarios?

a. 5 Eye Color Genes:

b. 10 Eye Color Genes:

c. 20 Eye Color Genes:

6 0

1 year ago

QUESTION 17

borishaifa [10]

Question 17:

False; cutting hair would change what it looks like but, braiding it keeps it the same substance it is.

Question 18 :

My best guess would either be A or D. I would lean more towards D because if there are different mixtures then it depends on what you are mixing.

Hope it helps in some way. <3

5 0

2 years ago

A student has a 2.19 L bottle that contains a mixture of O 2 , N 2 , and CO 2 with a total pressure of 5.57 bar at 298 K . She k

Sergeeva-Olga [200]

<u>Answer:</u> The partial pressure of oxygen gas is 2.76 bar

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 5.57 bar

V = Volume of the gas = 2.19 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0831\text{ L bar }mol^{-1}K^{-1}$

n = Total number of moles = ?

Putting values in above equation, we get:

$5.57bar\times 2.19L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{5.57\times 2.19}{0.0831\times 298}=0.493mol$

To calculate the mole fraction of carbon dioxide, we use the equation given by Raoult's law, which is:

$p_{A}=p_T\times \chi_{A}$ ........(1)

where,

$p_A$ = partial pressure of carbon dioxide = 0.318 bar

$p_T$ = total pressure = 5.57 bar

$\chi_A$ = mole fraction of carbon dioxide = ?

Putting values in above equation, we get:

$0.318bar=5.57bar\times \chi_{CO_2}\\\\\chi_{CO_2}=\frac{0.381}{5.57}=0.0571$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

We are given:

Moles of nitrogen gas = 0.221 moles

Mole fraction of nitrogen gas, $\chi_{N_2}=\frac{0.221}{0.493}=0.448$

Calculating the partial pressure of oxygen gas by using equation 1, we get:

Mole fraction of oxygen gas = (1 - 0.0571 - 0.448) = 0.4949

Total pressure of the system = 5.57 bar

Putting values in equation 1, we get:

$p_{O_2}=5.57bar\times 0.4949\\\\p_{O_2}=2.76bar$

Hence, the partial pressure of oxygen gas is 2.76 bar

6 0

3 years ago

Whose work is credited with being the beginning of the modern atomic theory

Damm [24]

Democritus (460-370 BC) was a Greek philosopher who theorized that all matter could be reduced to particles that could not be divided, which he described as “atomos.”

John Dalton (1766-1844) Proposed the atomic theory.

7 0

3 years ago