Which atom or ion is the largest? A. K B. K+ C. Ca D. Ca2+ E. Li
1 answer:
Answer:
A. K
Step-by-step explanation:
Remember the trends in the Periodic Table:
- Atomic radii <em>decrease</em> from left to right across a Period.
- Atomic radii <em>increase</em> from top to bottom in a Group.
- Ionic radii of metal cations are <em>smaller</em> than those of their atoms.
Thus, the largest atoms are in the lower left corner of the Periodic Table.
The diagram below shows that K is closest to the lower left, so it is the largest atom. It is also larger than any of the cations.
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Answer: 12
Explanation.
This problem was recently posted and deals with the conversion of units,so I give the same answer.
You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.
The conversion of units is easily undertaken once you build your conversion factors.
Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.
Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.
Then, build your conversion factor from the definitions given:
- 12 sleps is equal to 9 quibs.
- 12 sleps = 9 quibs
- in virtue of the division property of equality, you can divide both sides by 12 sleps and get:
1 = 12 sleps / 9 quibs ← conversion factor
Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:
- identity property: 9 quibs = 9 quibs × 1
- substitution property: 9 quibs = 9 quibs × 12 sleps/ 9 quibs
You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.
So, all you have to do now is the operations with the numbers:
9 quibs = (9 × 12 / 9) sleps = 12 sleps ← answer