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MatroZZZ [7]
2 years ago
15

Check my answers please? Only 5...Will reward medal to best answer and perhaps become a fan! :)

Chemistry
1 answer:
stellarik [79]2 years ago
5 0
The correct answer is <span>Fusion Curve</span>
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Specific gravity of a vegetable oil is 0.85. What is its density?
elena-s [515]
I think its density is 850kg/m^3
6 0
2 years ago
Calculate the eccentricity of an ellipse. The distance between the foci is 5.2 and the length of the major axis is 20.6.Round of
Dominik [7]

Answer:

The eccentricity of the ellipse is 0.252.

Explanation:

The eccentricity of an ellipse (c), dimensionless, can be determined by means of the following expression:

e = \frac{\bar c}{\bar a} (1)

Where:

\bar c - Distance between the foci, dimensionless.

\bar a - Length of the major axis, dimensionless.

If we know that \bar c = 5.2 and \bar a = 20.6, then the eccentricity of the ellipse is:

e = \frac{5.2}{20.6}

e = 0.252

The eccentricity of the ellipse is 0.252.

8 0
3 years ago
hich of the followings decrease the affinity of adult Hb with O2? A. 2,3 BPG B. hydrogen ion C. CO2 D. Ferrous ion
Ivahew [28]

Answer:

A. 2,3 BPG

Explanation:

2,3-bisphosphoglycerate (BPG), otherwise known as 2,3-DPG, enables the transition of hemoglobin from a very high-oxygen-affinity state to a reduced-oxygen-affinity state.

Tissues hemoglobin oxygen affinity is reduced by numerous physiological factors including.

1. Temperature Increased,

2. Carbon dioxide,

3. Acid and

4. 2,3-Bisphosphoglycerate (2,3-BPG)

all of which can contribute to decrease the oxygen affinity of hemoglobin which favours unloading and increased oxygen availability to our body cells.

3 0
2 years ago
Weather is not the same as climate. Which claim
Natalka [10]
C ........................
6 0
2 years ago
Read 2 more answers
How many moles of BCl3 are needed to produce 10.0 g of HCl(aq) in the following reaction? (HCl molar mass is 36.46 g/mol).
Scilla [17]

Answer:

Moles of BCl₃ needed = 0.089 mol

Explanation:

Given data:

Moles of BCl₃ needed = ?

Mass of HCl produced = 10.0 g

Solution:

Chemical equation:

BCl₃ + 3H₂O  →     3HCl + B(OH)₃

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 36.46 g/mol

Number of moles = 0.27 mol

Now we will compare the moles of HCl with BCl₃.

               HCl             :           BCl₃

                 3               :             1

             0.27             :            1/3×0.27 = 0.089 mol

6 0
2 years ago
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