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3 years ago

Consider this reaction:

Chemistry

1 answer:

dedylja [7]3 years ago

8 0

Answer:

0.13 M ( 2 s.f)

Explanation:

2Cl2O5 (g)-->2Cl2(g) +5O2 (g)

rate= (17.4 M -1 .s -1 ) [Cl2O5]2

From the rte above, we can tell that our rate constant (k) = 17.4 M -1 .s -1

The units of k tells us this is a second order reaction.

Initial Concentration [A]o = 1.46M

Final Concentration [A] = ?

Time = 0.400s

The integrated rate law for second order reactions is given as;

1 / [A] = (1 / [A]o) + kt

1 / [A] = [ (1/ 1.46) + (17.4 * 0.4) ]

1 / [A] = 0.6849 + 6.96

1 / [A] = 7.6496

[A] = 1 / 7.6496

[A] = 0.13073 M ≈ 0.13 M ( 2 s.f)

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Read 2 more answers

For most solids at room temperature, the specific heat is determined by oscillations of the atom cores in the lattice (each osci

Cloud [144]

Answer:

The specific heat of copper is $C= 392 J/kg\cdot ^o K$

Explanation:

From the question we are told that

The amount of energy contributed by each oscillating lattice site is $E =3 kT$

The atomic mass of copper is $M = 63.6 g/mol$

The atomic mass of aluminum is $m_a = 27.0g/mol$

The specific heat of aluminum is $c_a = 900 J/kg-K$

The objective of this solution is to obtain the specific heat of copper

Now specific heat can be defined as the heat required to raise the temperature of 1 kg of a substance by $1 ^o K$

The general equation for specific heat is

$C = \frac{dU}{dT}$

Where $dT$ is the change in temperature

$dU$ is the change in internal energy

The internal energy is mathematically evaluated as

$U = 3nk_BT$

Where $k_B$ is the Boltzmann constant with a value of $1.38*10^{-23} kg \cdot m^2 /s^2 \cdot ^o K$

T is the room temperature

n is the number of atoms in a substance

Generally number of atoms in mass of an element can be obtained using the mathematical operation

$n = \frac{m}{M} * N_A$

Where $N_A$ is the Avogadro's number with a constant value of $6.022*10^{23} / mol$

M is the atomic mass of the element

m actual mass of the element

So the number of atoms in 1 kg of copper is evaluated as

$m = 1 kg = 1 kg * \frac{10000 g}{1kg } = 1000g$

The number of atom is

$n = \frac{1000}{63.6} * (6.0*0^{23})$

$= 9.46*10^{24} \ atoms$

Now substituting the equation for internal energy into the equation for specific heat

$C = \frac{d}{dT} (3 n k_B T)$

$=3nk_B$

Substituting values

$C = 3 (9.46*10^{24} )(1.38 *10^{-23})$

$C= 392 J/kg\cdot ^o K$

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3 years ago