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3 years ago

What qualities make one theory "better" than another in the scientific community?

1 answer:

5 0

Some theories may have better reasoning than others. Sometimes, it even depends on who made the theory. If a highly respected scientist made a theory, his or hers may be looked at as better than others,

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A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

Ede4ka [16]

Answer: The mass of glucose in final solution is 1.085 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

4 0

3 years ago

You need to determine the mass of an aqueous solution. You determine the mass of your 10.0 mL graduated cylinder to be 23.731 g.

Amanda [17]

Answer: 0.86g/mL

Explanation:

Mass of empty cylinder = 23.731g

Mass of cylinder + liquid = 26.414g

Mass of the liquid = 26.414 — 23.731

= 2.683g

Volume of the liquid = 3.12mL

Density = Mass / volume

Density = 2.683g / 3.12mL

Density = 0.86g/mL

3 0

3 years ago

Why do the deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer?

rodikova [14]

Answer:

The deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer because Organic compounds that are neither acids or bases do not react with either NaOH or HCl and, therefore remain more soluble in the organic solvent and are not extracted.

Explanation:

4 0

3 years ago

Sunlight is composed of energy that is visible to humans and energy that is not visible to humans. Which statement describes how

Vilka [71]

Answer:

both forms of energy referred to in the question is light and heat energy

light energy is the visible energy that travels at a known constant speed of 3.0×10^9m/s

while heat energy is the invisible energy that travels in form of radiation at variable speeds

4 0

2 years ago

A solution of an acid could have a pH of __* 3 to 5 6 to 8 9 to 11 12 to 14

sdas [7]

Answer:

3 to 5

Explanation:

The pH scale is from 0 to 14.

Acids have a pH of anything less than 7.

Anything with a pH greater than 7 is considered to be a base.

If a solution has a pH of 7, it is neutral.

3 to 5 is in the range of less than 7, so a solution of an acid can have this pH.

6 to 8 includes less than 7 , 7 and greater than 7, so it is not just in the range of an acid.

9 to 11 and 12 to 14 are both in the range of greater than 7, so they have to be bases.

Therefore, the correct answer is 3 to 5.

4 0

3 years ago