The percent by weight (w/w%) of sugar in soda : 6.216%
<h3>Further explanation</h3>
Given
mass of sugar = 23 g
total mass = 370 g
Required
the percent weight
Solution
%weight = (mass of solute : mass of solution) x 100%
solute = sugar
solution = solvent + solute = water + sugar
percent weight of sugar in soda :
= (23 : 370) x 100%
= 6.216 %
Answer:
4
Explanation:
The zeros before a non zero digit do not count as significant figures so there are 4 sig figs in the number
Answer:
4
Explanation:
There are 4 significant figures because when there is not a decimal, then only numerical values over 0 are counted. So the numbers counted in sig figs are 2049, and none of the other 0s.
So if it was 204,900,000,000.0, then it would have 12 significant figures.
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Explanation:
In the combustion reaction methane (CH₄) will react with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O).
CH₄ + O₂ → CO₂ + H₂O
To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.
So the balanced chemical reaction will be:
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Learn more about:
balancing chemical equations
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