Answer:
B. 400 kPa
Explanation:
the pressure increases, when the temperature increases. and it increases, when the volume decreases.
both cases happen here, each with the factor 2.
so, the pressure increases by the factor 2×2 = 4.
4×100 = 400 kPa
Answer:
The new volume will be 5.80 L
Explanation:
Step 1: Data given
The initial volume = 29.0 L
The initial pressure = 562 torr = 562 /760 atm = 0.739474 atm
The pressure changes to 2810 torr = 2810 /760 atm = 3.697368 atm
The temperature and number of moles will not change
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒With P1 = the initial pressure = 0.739474 atm
⇒with V1 = the initial volume = 29.0 L
⇒with P2 = the increased pressure = 3.697368 atm
⇒with V2 = The new volume = TO BE DETERMINED
0.739474 atm * 29.0 L = 3.697368 atm * V2
V2 = 5.80 L
OR
562 torr * 29.0 L = 2810 torr * V2
V2 = 5.80 L
The new volume will be 5.80 L
Answer:
no, Charon is significantly smaller than Mercury
Answer:
22.73s
Explanation:
The reaction is a second order reaction, we know this by observing the unit of the slope.
rate constant = k = 0.056 M-1s-1
the initial concentration of BrO- [A]o = 0.80 M
time = ?
Final concentration [A]t= one-half of 0.80 M = 0.40M
1 / [A]t = kt + 1 / [A]o
1 / 0.40 = 0.056 * t + 1 / 0.80
t = (2.5 - 1.25) / 0.056
t = 22.73s
The answer is B. 6CO2+H2O yields C6H12O6+ 6H20.
