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2 years ago

Calculate the answer. Express it in scientific notation. All answers should have the correct number of significant figures.

Chemistry

2 answers:

beks73 [17]2 years ago

8 0

(1.632) (4.0 x 104)

= (1.632)(416)

=678.912

6.8* 10^2.

Not sure if it's the right sig figs.

mamaluj [8]2 years ago

4 0

Answer:

417.632 (i dont know if u need to round or somehting but this is what i think is right)

Explanation:

4.0 x 104 = 416

(1.632) (416) = 417.632

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3 years ago

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2 years ago

Suppose you have just added 200.0 ml of a solution containing 0.5000 moles of acetic acid per liter to 100.0 ml of 0.5000 M NaOH

uranmaximum [27]

Answer:

The final pH is 3.80

Explanation:

Step 1: Data given

Volume of acetic acid = 200.0 mL = 0.200 L

Number of moles acetic acid = 0.5000 moles

Volume of NaOH = 100.0 mL = 0.100 L

Molarity of NaOH = 0.500 M

Ka of acetic acid = 1.770 * 10^-5

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles

moles = molarity * volume

Moles NaOH = 0.500 M * 0.100 L

Moles NaOH = 0.0500 moles

Step 4: Calculate the limiting reactant

For 1 mol CH3COOH we need 1 mol NaOH to produce 1 mol CH3COONa and 2 moles H2O

NaOH is the limiting reactant. It will completely be consumed (0.0500 moles). CH3COOH is in excess. There will react 0.0500 moles . There will remain 0.500 - 0.0500 = 0.450 moles

There will be produced 0.0500 moles CH3COONa

Step 5: Calculate the total volume

Total volume = 200.0 mL + 100.0 mL = 300.0 mL

Total volume = 0.300 L

Step 6: Calculate molarity

Molarity = moles / volume

[CH3COOH] = 0.450 moles / 0.300 L

[CH3COOH] = 1.5 M

[CH3COONa] = 0.0500 moles / 0.300 L

[CH3COONa]= 0.167 M

Step 7: Calculate pH

pH = pKa + log[A-]/ [HA]

pH = -log(1.77*10^-5) + log (0.167/ 1.5)

pH = 4.75 + log (0.167/1.5)

pH = 3.80

The final pH is 3.80

7 0

3 years ago

What is the density of a cube that has a mass of 25 g in a volume of 125 cm 3

GalinKa [24]

<span>The density of an object is defined to be its mass divided by the volume it occupies. For this problem, the mass of the cube was given to be 25 g while its volume is 125 cm</span>³. Thus, we simply divide 25 g by 125 cm³ to get the object’s density. We then calculate that the cube has a density of 0.2 g/ cm³.

3 0

3 years ago

On the moon the acceleration due to gravity is 1.6 ms if an object has a mass on earth of 5.1kg what is its mass on the moon

Y_Kistochka [10]

Answer:

Mass on the moon is 5.1 kg.

Explanation:

Given mass on earth = 5.1 kg

acceleration due to gravity on moon = 1.6 ms⁻².

The mass on the moon does not change because mass is the quantity of matter in the body regardless of its volume or of any forces acting on it.

Whereas the weight of the object changed.

Weight is the the force exerted on a body which is related to mass and expressed as W = mg.

W = weight of object m = mass of object and g = gravitational force

$So\ in\ this\ case\ W\ =1.6\times\ 5.1\ =8.16N$

N stands for newton unit of weight.

Thus mass of the object on moon is same as on earth which is 5.1 kg.

3 0

2 years ago