Answer:
(-4v-5)-(v-1)= -5v-4
Step-by-step explanation:
hope it helps :D
QUESTION 1
The given expression is
![12x^4+18x^3+45x^2](https://tex.z-dn.net/?f=12x%5E4%2B18x%5E3%2B45x%5E2)
The greatest common factor is
.
We factor to obtain;
![3x^2(4x^2+6x+15)](https://tex.z-dn.net/?f=3x%5E2%284x%5E2%2B6x%2B15%29)
QUESTION 2
The given quadratic equation is
![x^2+6x-72=0](https://tex.z-dn.net/?f=x%5E2%2B6x-72%3D0)
We split the middle term to obtain
![x^2+12x-6x-72=0](https://tex.z-dn.net/?f=x%5E2%2B12x-6x-72%3D0)
Factor by grouping;
![x(x+12)-6(x+12)=0](https://tex.z-dn.net/?f=x%28x%2B12%29-6%28x%2B12%29%3D0)
![(x+12)(x-6)=0](https://tex.z-dn.net/?f=%28x%2B12%29%28x-6%29%3D0)
Use zero product property;
![(x+12)=0\:\:or\:\:(x-6)=0](https://tex.z-dn.net/?f=%28x%2B12%29%3D0%5C%3A%5C%3Aor%5C%3A%5C%3A%28x-6%29%3D0)
![x=-12\:\:or\:\:x=6](https://tex.z-dn.net/?f=x%3D-12%5C%3A%5C%3Aor%5C%3A%5C%3Ax%3D6)
QUESTION 3
The given system of equation is
![3x+4y=-8](https://tex.z-dn.net/?f=3x%2B4y%3D-8)
![7x-3y=6](https://tex.z-dn.net/?f=7x-3y%3D6)
If we multiply
by 3, we obtain;
![9x+12y=-24](https://tex.z-dn.net/?f=9x%2B12y%3D-24)
If we multiply
by 4 we obtain;
![28x-12y=24](https://tex.z-dn.net/?f=28x-12y%3D24)
Adding the last two equations will give us;
![37x=0](https://tex.z-dn.net/?f=37x%3D0)
The y-variable is eliminated.
Answer:Multiply 3x+4y=−8
by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.
The answer is x=-5 hope that helps