Ask question

Ask question

All categories

4 years ago

8

Verify the identity. Help please!!!

1 answer:

MariettaO [177]4 years ago

4 0

The given expression can be proved using the Pythagorean identity as shown below:

$L.H.S \\ \\ 
= 1+ sec^{2} *sin^{2}x \\ \\ 
=1+ \frac{1}{cos^{2}x } sin^{2}x \\ \\
=1+tan^{2}x \\ \\ 
=sec^{2}x \\ \\ 
= R.H.S 
$

Thus, the Left hand side has been proved equal to Right Hand Side.

You might be interested in

HELP ME!!!!!!!!!!!!!!!!!!!!!!!!! =-I

vredina [299]

Number 6 is not a reasonable answer so I agree

3 0

3 years ago

Solve (x + 9)2 = 25. Apply the square root property of equality: Isolate the variable. StartRoot (x + 9) squared EndRoot = Plus

Licemer1 [7]

Answer:1

Step-by-step explanation: I dont know

4 0

4 years ago

Read 2 more answers

The end of a house has the shape of a square surmounted by an equilateral triangle. If the length of the base is measured to be

sergij07 [2.7K]

Answer:

The area of the end is 1755.44 ft²

Therefore, the maximum error in calculating area of the end is 8.3592

Step-by-step explanation:

Consider the provided information.

The length of the base is measured to be 35 feet, with a maximum error in measurement of 1 inch,

$1\ inch = \frac{1}{12}\ feet$

The area of shape = Area of square + Area of equilateral triangle

$A=x^2+\frac{\sqrt{3}}{4}x^2$

Substitute x=35 in above.

$A=(35)^2+\frac{\sqrt{3}}{2}\times (35)^2=1755.44$

Hence, the area of the end is 1755.44 ft²

Differentiate $A=x^2(1+\frac{\sqrt{3}}{4})$ with respect to x as shown:

$dA=2x\ dx(1+\frac{\sqrt{3}}{4})$

Substitute dx =1/12 and x=35

$dA=2(35)\ \frac{1}{12}(1+\frac{\sqrt{3}}{4})=8.3592$

Therefore, the maximum error in calculating area of the end is 8.3592

6 0

3 years ago

Noah says that 9x − 2x + 4x is equivalent to 3x because the subtraction sign tells us to subtract everything that comes after 9x

Genrish500 [490]

Answer:

Noah's claim is correct

Step-by-step explanation:

B O D M A S - Brackets, Over, Division, Multiplication, Addition and Subtraction, this means that you must do the addition first.

2x+ 4x = 6x

9x - 6x = 3x

Noah is correct as the - sign tells us that you have to subtract everything after the 9x

Hope this is ok and helps a little bit

5 0

3 years ago

Joe's annual income has been increasing in the same dollar amount. The first year his income was $15,200, and the 4th year his i

lidiya [134]

Answer:

Therefore 6th year his income was $19,700.

Step-by-step explanation:

Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th year his income was $17,900.

A=$17900, P= $15,200 and n = 3 year

$A= P(1+\frac{r}{100} )^n$

$\Leftrightarrow 17900=15200(1+\frac{r}{100})^3$

$\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}$

$\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }$

$\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1$

$\Leftrightarrow r=5.60$

Let $t^{th}$ year Joe's income was $19,700.

$\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}$

$\Leftrightarrow 1.296= (1+0.056)^{t-1}$

$\Leftrightarrow 1.296= (1.056)^{t-1}$

$\Leftrightarrow log(1.296)= (t-1)log(1.056)$

$\Leftrightarrow \frac{log(1.296)}{log(1.056)}= (t-1)$

$\Leftrightarrow t-1= 4.75$

$\Leftrightarrow t= 4.75+1$

$\Leftrightarrow t = 5.75$ ≈6

Therefore 6th year his income was $19,700.

8 0

3 years ago