The energy of a photon is given by

where h is the Planck constant and f is the photon frequency.
We can find the photon's frequency by using the following relationship:

where c is the speed of light and

is the photon's wavelength. By plugging numbers into the equation, we find

And so now we can find the photon energy

We know that 1 Joule corresponds to

So we can convert the photon's energy into electronvolts:
This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.
The height of the hill is "166.76 m".
<h3>LAW OF CONSERVATION OF ENERGY:</h3>
According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:

where,
- h = height of the hill = ?
= maximum velocity = 57.2 m/s
- g = acceleration due to gravity = 9.81 m/s²
Therefore,

<u>h = 166.76 m</u>
Learn more about the law of conservation of energy here:
brainly.com/question/101125
Answer:
(a) hypermetropia
(b) convex lens
(c) 133.33 cm
(d) - 21.05 cm
Explanation:
(a) As she is old age, so she is suffering from hypermetropia.
(b) It is the defect due to which a person is not able to see the nearby objects clearly, so it is cured by convex lens of suitable focal length.
(c) Power, P = + 0.75 D
Focal length is the reciprocal of power of lens.
f = 1/ P = 1/0.75
f = 133.33 cm
(d) v = -25 cm, f = 133.3 cm
use lens equation



u = - 21.05 cm
The braking distance is given by 
Explanation:
When the driver of a car hits the pedal of the brakes, the car starts decelerating until it stops. Assuming the deceleration is constant, then the motion is a uniformly accelerated motion, so we can use the following suvat equation:

where
u is the initial speed of the car
v is the final speed of the car, which is zero because the car comes to rest:
v = 0
a is the acceleration of the car
s is the distance travelled by the car during the deceleration, so it is the braking distance
Therefore, re-arranging the equation for s, we find an expression for the braking distance:

Note that the sign of
is negative since the car is decelerating, therefore the final sign of
is positive.
Learn more about accelerated motion:
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