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Nimfa-mama [501]
3 years ago
5

A machine is designed to lift an object with a weight of 12 newtons. If the input force for the machine is set

Physics
1 answer:
anzhelika [568]3 years ago
8 0

Answer:

m = 1.5

Explanation:

We have,

The input force for the machine is set is 8 N and the machine is designed to lift an object with a weight of 12 newtons.

We need to find the mechanical advantage of the machine. It is defined as the ratio of output force to the input force. Its formula is given by :

m=\dfrac{F_o}{F_i}\\\\m=\dfrac{12}{8}\\\\m=1.5

So the mechanical advantage of the machine is 1.5

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If we decrease the amount of force applied to an object, and all other factors remain the same, the amount of work completed wil
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A ) decrease.
B ) increase.
C ) increase, then decrease.
D ) not change.

The answer is A) decrease

Take pushing a box, for example-- You  push your hardest then give out, still trying to push the box. You are doing less work than what you have started with!

( Mind marking me for branliest? ; ) )
4 0
3 years ago
What is the average velocity of a bowling ball that moves down the lane 8 meters in 4 seconds?​
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Answer: 2m/s

Explanation:

V avg = Displacement / time

Displacement is 8

Time is 4

V avg = 2

8 0
3 years ago
Suppose the electric field in some region is found to be E = kr3 ˆr, in spherical coordinates (k is some constant). (a) Find the
Assoli18 [71]

Answer:

Part a)

\rho = 3\epsilon_0 k r^2

Part b)

Q = 4\pi \epsilon_0kR^5

Explanation:

Part a)

As we know that electric field intensity due to some given charge distribution is given as

E = kr^3 \hat r

now electric flux through a spherical surface of radius r is given as

\phi = E. A

\phi = kr^3(4\pi r^2)

now by Guass law we know that

E.A = \frac{q}{\epsilon_0}

q = 4\pi \epsilon_0kr^5

now volume charge density is given as

\rho = \frac{q}{\frac{4}{3}\pi r^3}

\rho = 3\epsilon_0 k r^2

Part b)

Total charge inside the radius R is given as

Q = 4\pi \epsilon_0kR^5

7 0
3 years ago
The reaction energy of a reaction is the amount of energy released by the reaction. It is found by determining the difference in
solmaris [256]

Answer: the correct answer is 7.8026035971 x 10^(-13) joule

Explanation:

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m = 4.00260 u + 222.01757 u = 226.02017 u .

The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is

Delta m = 226.02540 u - 226.02017 u = 0.00523 u ,

which is equivalent to an energy change of

Delta E = (0.00523 u)*(931.5MeV/1u)

Delta E = 4.87 MeV

Converting  4.87 MeV to Joules

1 joule [J] = 6241506363094 mega-electrón voltio [MeV]

4 mega-electrón voltio = 6.40870932 x 10^(-13) joule

4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule

5 0
4 years ago
Inside a NASA test vehicle, a 3.50-kg ball is pulled along by a horizontal ideal spring fixed to a friction-free table. The forc
erastova [34]
F(of spring)=230x=ma=3.5(5)=17.5=230x; x=0.07m.
3 0
3 years ago
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