The store has 28 notebooks in packs of 4 three packs are sold how many packs of notebooks are left

Evaluate intergral 10xe exponent 10x dx

Shtirlitz [24]

Answer:

for this type of question, integral by parts should be used . This involves using the formula for intregation by parts:

intudv=uv-intvdu.

lets first break apart the x and e10x into two parts - "u" and "v"

where u = x.

however, we need to find the value of v. in order to do this, we can integrate dv/dx in order to get to v.

the value of dv/dx is : e10x

u = x dv/dx = e10x

as seen in the formula, you need to have a value for u, dv, v and du.

therefore in order to get du you must differentiate u:

u = x

du/dx = 1

du = 1dx = dx

du = dx

in order to get v you need to integrate dv/dx:

\displaystyle \inte10x dx = 1/10 x10x

now that we have both parts, we can put this back into the formula.

intudv=uv-intvdu.

\displaystyle \intxe10x = x * 1/10e10x - \displaystyle \int1/10e10x dx

Step-by-step explanation:

5 0

3 years ago

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Marisa wants to buy a quality phone for least $200.She has already saved $125 and plans to save an additional $10 each week.Writ

eduard

Answer:

The inequality can be represented as:

$10w+125\geq200$

where $w$ represents the number of weeks in which Maria will be able to buy a phone for least $200.

On solving it we get : $w\geq 7.5$

Step-by-step explanation:

Given:

Maria wants to buy a phone for at least $200.

She has savings of $125.

She plans to save $10 every week.

To write an inequality for the situation.

Solution:

Let the number of weeks in which Maria will be able to buy a phone be = $w$

If she saves $10 each week.

Then, in $w$ weeks she will save in dollars = $10w$

She already has savings = $125

So her total savings in $w$ weeks in dollars will be = $10w+125$

She wants to buy a phone for at least $200.

Thus, the inequality can be represented as:

$10w+125\geq200$

Solving for $w$

Subtracting both sides by 125.

$10w+125-125\geq 200-125$

$10w\geq 75$

Dividing both sides by 10.

$\frac{10w}{10}\geq \frac{75}{10}$

$w\geq 7.5$

Thus Maria needs at least 7.5 weeks to be able to buy a phone for atleast $200.

5 0

3 years ago

Katrina wants to estimate the proportion of adults who read at least 10 books last year. to do so, she obtains a simple random

Vaselesa [24]

E=Z*sqrt (p(1-p)/N), where E= error margin, p=proportion, N=sample size

Katrina's margin error at 85% confidence interval: E=1.96*sqrt (p(1-p)/100) = 0.196 sqrt (1(1-p))

Mathew's margin error at 99% confidence interval: E= 2.58*sqrt (p(1-p)/400) = 0.129 sqrt (p(1-p))

Since both obtained same estimate of proportion (that is, value of p), it can be seen that Mathew's estimate will have a small error (That is, 0.129 is smaller than 0.196). This can be attributed to larger sample size although a wider confidence (99%) interval was considered.

3 0

3 years ago

Jim earns $1,600 per month after taxes. He is working on his budget and has the first three categories finished. Housing $576 Fo

Afina-wow [57]

B.

He has used the highest recommended percentages to calculate the amounts for the three categories.

5 0

3 years ago

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What is the product? (-2d^2+s)(5d^2-6s)

Ulleksa [173]

(-2d^2+s)(5d^2-6s)
= (-2d^2*5d^2 + s*5d^2 -2d^2*-6s + s*-6s
= -10d^4 + 5sd^2 + 12sd^2 - 6s^2
=-10d^2 + 17sd^2 - 6s^2
This is the final result