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Rainbow [258]
2 years ago
15

Anu and Aji solve an equation. In solving Anu commits a mistake in constant term and finds the roots 8 and 2. Aji commits a mist

ake in the coefficient of x. The correct roots are (a) 9,1 (b)-9,1 (c) 9, -1 (d) -9.-1​
Mathematics
1 answer:
vagabundo [1.1K]2 years ago
5 0

The correct roots of the equation are (a) 9 and 1

From the complete question, their mistakes are:

<u>Anu</u>

  • Roots: 8 and 2
  • Wrong constant term

<u>Aji</u>

  • Roots: -9 and -1
  • Wrong coefficient

A quadratic equation is represented as:

ax^2 + bx + c = 0

Where:

\alpha\beta = \frac ca --- product of roots

\alpha + \beta = -\frac ba --- sum of roots

Anu made a mistake in the constant term, so we consider the sum of roots

Sum = 8 + 2

Sum = 10

Aji made a mistake in the coefficient, so we consider the product of roots

Product = -9 \times -1

Product = 9

The possible equations from the above sum and products are:

  • x^2 + 10x  + 9 =0.
  • x^2 - 10x  + 9 =0.
  • x^2 + 10x  - 9 =0.
  • x^2 - 10x  - 9 =0

Of all the above equations, the most likely equation is x^2 - 10x  + 9 =0, and it has a root of 9 and 1

Hence, the correct roots are (a) 9 and 1

Read more about roots of equations at:

brainly.com/question/3923172

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