The average amount of corn produced per acre represented in scientific notation can be found using the below formula:

We are given:

Substituting the above information in the formula, we get...

Conclusion:

The average amount of corn produced per acre represented in scientific notation is option B)
bushels per acre
Y=2x-1
y=-3x+14
First you would substitue one of the y's for the other so
2x-1=-3x+14
no you would solve for x...
add one on both sides
2x=-3x+15
now add 3x to both sides which becomes
5x=15
divide 5 on both sides which gives you x=3
now to solve for y plug into any one of the equations(doesn't matter which one) from before 3 for x and solve
y=2(3)-1
y=6-1
y=5
And that is you answer y=5
<span>The graph of g(x)=⌈x⌉+0.5 is the graph of f(x)=⌈x⌉ shifted up 0.5 unit.</span>
Hello Croary
We would first need to subtract 13.09cm from 21.59cm which will be 8.5cm, with the left over space, divide in half
<u><em>8.5/2 = 4.25cm</em></u>
:)
2.36 repeating
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