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3 years ago

Name the additive inverse and the multiplicative inverse for the number 2.5

Mathematics

1 answer:

GrogVix [38]3 years ago

3 0

Answer:

i can't see it

Step-by-step explanation:

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3 years ago

15 inches of snow fell in 12 hours. At this rate, how many inches of snow will fall in 3 days.

kirill [66]

Answer:

90 in

Step-by-step explanation:

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3 years ago

Read 2 more answers

How to solve -8+squre root (5a-5)=-3

sertanlavr [38]

Answer:

$a=6$

Step-by-step explanation:

Given equation:

$-8+\sqrt{5a-5}=-3$

Solving for unknown variable $a$

Adding 8 both sides by additive property of equality.

$+8-8+\sqrt{5a-5}=-3+8$

$\sqrt{5a-5}=5$

Squaring both sides to remove the square root.

$(\sqrt{5a-5})^2=5^2$

$5a-5=25$

Adding 5 both sides by additive property of equality.

$5a-5+5=25+5$

$5a=30$

Dividing both sides by 6 to isolate $a$

$\frac{5a}{5}=\frac{30}{5}$

∴ $a=6$

8 0

3 years ago

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

8 0

3 years ago