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nika2105 [10]
4 years ago
15

Write x squared + 2x-8 in the form (x + m) squared + n where m and n are integers.

Mathematics
1 answer:
skelet666 [1.2K]4 years ago
7 0
Let F(x) = x^2 + 2x -8

Adding 1 and - 1 at equation

F(x) = x^2 + 2x + 1 - 1 -8

Rewrinting the first 1 = 1^2

F(x) = x^2 + 2x + 1^2 - 1 - 8

Now look:

x^2 + 2x + 1^2 = ( x + 1)^2

Then,

F(x) = (x + 1)^2 -1 -8

F(x) = (x + 1)^2 -9

This is the answer !

If us to want.

(x + 1)^2 -9 = ( x+1)^2 - 3^2

= ( x+ 1 -3).(x +1 +3)

= ( x - 2).(x +4)

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olganol [36]
<h3>Answer:  (x+1)(x+3)</h3>

===================================================

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Let's assume it factors into (x+a)(x+b)

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Note how a+b is the middle term and ab is the last term.

In the original expression, 4 is the middle term and 3 is the last term.

So we need to find two numbers that

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