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Tanzania [10]
3 years ago
9

An electronics store makes a profit of 48 for every television sold and 60 for every computer sold the manager target is to make

at least 240ns what are three possible solutions to the problem
Mathematics
1 answer:
gregori [183]3 years ago
8 0

Answer:

1)On selling 4 computers, the target is matched.

2)By selling 5 televisions, the target is matched.

3) Selling 3 televisions and 3 computers, the target is matched.

Step-by-step explanation:

The profit on each television sold  = 48

The profit on every computer sold = 60

Now, the targeted profit is  ≥240

(1)  As, the profit on each computer = 60

⇒The profit on selling 6 computer = 4 ( Profit one each computer)

= 4 x 60 = 240

Hence, on selling 4 computers, the target is matched.

(2)  As, the profit on each television = 48

⇒The profit on selling 5 television = 5 ( Profit one each 5 television)

= 5 x 48 = 240

Hence, on selling 5 televisions, the target is matched.

(3) Now, by selling 3 Televisions, the profit = 2 x 48  = 96

by selling 3 computers, the profit =  3 x 60 = 180

Total profit =  96 + 180 = 276  > 240

Hence, on selling 3 televisions and 3 computers, the target is matched.

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Answer:

(0.88, 0,65)

Step-by-step explanation:

what do we have to do ? I assume we need to find the crossing point between the 2 lines.

when looking at the graphic, we can already rule out the first, third and fourth option.

none of the coordinates of that point is larger than 1 in any direction or smaller than 0.5.

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but let's check.

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for the crossing point both functions must produce the same functional value.

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Firlakuza [10]
\(\begin{matrix}
y=ln(x+3)\\
e^y=x+3\\
e^y-3=x\\
swap ~x~and~y\\
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To get the inverse of any function f(x) [ just make sure that it passes the horizontal line test] follow the steps:

- Solve for x, i.e separate x in one side and the other terms in the other side, included f(x).

- Swap x and f(x).

- The result is the inverse of the original function f^{-1}(x).

-------------------------

Apply that on your function
\(\begin{matrix}
y=ln(x+3)\\
e^y=x+3\\
e^y-3=x\\
swap ~x~and~y\\
 \huge\underline{y=e^x-3}}
 \end{matrix}\)




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