Let distance between player A and B be x
from,
v = u + at
but,
v = u - gt, for the ball to be acted upon by gravity.
and the negative is to show the direction of g which is down.
u = initial speed(avg speed)
v will be 0m/s since it'll rest after reaching player B.
then,
0= u - (9.8*1.2)
0 =u - 11.76 m/s
u = 11.76 m/s
Therefore, the avg speed is 11.76m/s
Answer:
The minimun height is 242 [m]
Explanation:
We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy. We will take the point where the Falcon reaches the speed of 69 (m/s), as the point where the potential energy is zero, i.e. it will be the reference point.
At the reference point all potential energy has been transformed into kinetic energy, therefore the kinetic energy can be calculated.
![E_{k}=0.5*m*v^{2} \\ where:\\v = velocity = 69 [m/s]\\m = mass = 480[g] = 0.480[kg]\\E_{k} = kinetic energy [J]\\E_{k} =0.5*0.48*(69)^{2} \\E_{k} =1142.64[J]](https://tex.z-dn.net/?f=E_%7Bk%7D%3D0.5%2Am%2Av%5E%7B2%7D%20%5C%5C%20where%3A%5C%5Cv%20%3D%20velocity%20%3D%2069%20%5Bm%2Fs%5D%5C%5Cm%20%3D%20mass%20%3D%20480%5Bg%5D%20%3D%200.480%5Bkg%5D%5C%5CE_%7Bk%7D%20%3D%20kinetic%20energy%20%5BJ%5D%5C%5CE_%7Bk%7D%20%3D0.5%2A0.48%2A%2869%29%5E%7B2%7D%20%5C%5CE_%7Bk%7D%20%3D1142.64%5BJ%5D)
Now we can calculate the elevation with respect to the reference point using the definition of the potential energy.
![E_{p}=m*g*h\\ E_{p}=E_{k} \\therefore\\h= E_{p}/(m*g)\\h= 1142.64/(.48*9.81)\\h=242[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%20E_%7Bp%7D%3DE_%7Bk%7D%20%5C%5Ctherefore%5C%5Ch%3D%20E_%7Bp%7D%2F%28m%2Ag%29%5C%5Ch%3D%201142.64%2F%28.48%2A9.81%29%5C%5Ch%3D242%5Bm%5D)
Refraction is the bending of a wave as it passes at an angle from on medium to another
John Dalton laid the foundation for atomic theory.
Hope this helps!