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Ronch [10]
3 years ago
9

Help me please (。'-‿-。)​

Physics
2 answers:
Akimi4 [234]3 years ago
7 0

Answer:

the layers of atmosphere are heated through radiation and convection.

Explanation:

  • heat is transferred from sun through radiation

  • and current through convection
IceJOKER [234]3 years ago
3 0

Answer:

<h3>The layers of atmosphere are heated through </h3><h2><em>Convection</em><em> </em><em>and</em><em> </em><em>Radiation</em></h2>

Explanation:

The layers of atmosphere are heated through the Convection currents and the Radiation from Sun...

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An enemy spaceship is moving toward your starfighter with a speed, as measured in your frame, of 0.400c. The enemy ship fires a
kvasek [131]

Answer:

0.859375c

31.03 seconds

Explanation:

v' = Velocity of my ship = 0.4 c

u = Velocity of rocket = 0.7 c

c = Speed of light = 3\times 10^8\ m/s

s = Distance between my ship and enemy ship = 8\times 10^6\ km

Relativistic addition of speed is given by

v=\dfrac{v'+u}{1+\dfrac{uv'}{c^2}}\\\Rightarrow v=\dfrac{0.7+0.4}{1+\dfrac{0.7c\times 0.4c}{c^2}}\\\Rightarrow v=0.859375\ c

The speed of the missile is 0.859375c

Time is given by

t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{8\times 10^9}{0.859375\times 3\times 10^8}\\\Rightarrow t=31.03\ s

It will take 31.03 seconds to reach me.

6 0
3 years ago
A diffraction grating with 140 slits per centimeter is used to measure the wavelengths emitted by hydrogen gas. At what angles i
Degger [83]

Answer:

0.003181 radians

0.003005 radians

Explanation:

Number of slits = 140 /cm

λ = Wavelength = 434 nm = 434×10⁻⁹ m

m = 3 Third order spectrum

Space between slits

d=\frac{0.01}{140} =7.14\times 10^{-5}\ m

Now,

dsin\theta = m\lambda\\\Rightarrow \theta=sin^{-1}\left(\frac{m\lambda}{d}\right)\\\Rightarrow \theta=sin^{-1}\left(\frac{3\times 434\times 10^{-9}}{7.14\times 10^{-5}}\right)\\\Rightarrow \theta=sin^{-1}0.018228\\\Rightarrow \theta=0.01823^{\circ}=0.01823\times \frac{\pi}{180}=0.003181 radians

0.003181 radians

When λ = 410 nm = 410×10⁻⁹ m

dsin\theta = m\lambda\\\Rightarrow \theta=sin^{-1}\left(\frac{m\lambda}{d}\right)\\\Rightarrow \theta=sin^{-1}\left(\frac{3\times 410\times 10^{-9}}{7.14\times 10^{-5}}\right)\\\Rightarrow \theta=sin^{-1}0.01722\\\Rightarrow \theta=0.01722^{\circ}=0.01722\times \frac{\pi}{180}=0.003005 radians

0.003005 radians

5 0
3 years ago
Consider the program below:public class Test{ public static void main(String[] args) {Int[] a;a = new int[10];for(int i = 0; i &
ivolga24 [154]

Answer:

c. 65

Explanation:

The output is 65.

An array of length 10 is created first. Then, the first for-loop fill the array with different values; The array element now become: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11. The array element are generated using the equation a[i] = i + 2; so when i is 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. i must be less than the array length (10).

a[0] = 0 + 2 = 2

a[1] = 1 + 2 = 3

a[2] = 2 + 2 = 4

a[3] = 3 + 2 = 5

a[4] = 4 + 2 = 6

a[5] = 5 + 2 = 7

a[6] = 6 + 2 = 8

a[7] = 7 + 2 = 9

a[8] = 8 + 2 = 10

a[9] = 9 + 2 = 11

result variable is declared and initialized to 0.

The second for-loop goes through the array and add individual element to result.

6 0
3 years ago
While traveling along a highway a driver slows from 32 m/s and comes to a stop with an acceleration of -6 m/s2. How long did it
diamong [38]

Answer: 6s

Explanation:

Vs=32m/s  speed at beginning of slowing down

Vf=0m/s     stop speed

a= -6 m/s²  acceleration

----------------

Use equation for acceleration :

a=(Vf-Vs)/t

a*t=Vf-Vs

t=(Vf-Vs)/a

t=(0-36)/-6

t=-36/-6

t=6 s

7 0
3 years ago
What are the magnifications of the objective lenses
Anvisha [2.4K]

Answer:

Objective Lenses: Usually you find 3 or 4 objective lenses on a microscope. They almost always consist of 4x, 10x, 40x and 100x powers, when coupled with a 10x (most common) eyepiece lens, total magnification is 40x (4x times 10x) 100x, 400x and 1000x

Explanation:

Objective lenses come in various magnification powers, with the most common being 4x, 10x, 40x, and 100x, also known as scanning, low power, high power and typically oil immersion objectives, respectively

7 0
3 years ago
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