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Physics

2 answers:

Akimi4 [234]3 years ago

7 0

Answer:

the layers of atmosphere are heated through radiation and convection.

Explanation:

heat is transferred from sun through radiation

and current through convection

IceJOKER [234]3 years ago

3 0

Answer:

<h3>The layers of atmosphere are heated through </h3><h2><em>Convection</em><em> </em><em>and</em><em> </em><em>Radiation</em></h2>

Explanation:

The layers of atmosphere are heated through the Convection currents and the Radiation from Sun...

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Explain in detail what information can be learn about atoms of different elements by examining the periodic table . For the Maxi

raketka [301]

Answer:

We know the information about atomic size, energy, electronic configuration etc. of atom from the periodic table.

Explanation:

Periodic table is the arrangement of elements that are arranged according to their properties and electronic configuration.
In periodic table, on furthest right side of the periodic table, noble gases like He, Ne, Ar etc are arranged.
The atomic number of element increases while moving from left towards right in the periodic table.
The metallic character of element decreases as we proceed the table towards right.
They readily accept electron to fill the valence shell hence becoming more metallic in character.

5 0

3 years ago

A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km. 1. If you and your spacesuit

Law Incorporation [45]

1. 0.16 N

The weight of a man on the surface of asteroid is equal to the gravitational force exerted on the man:

$F=G\frac{Mm}{r^2}$

where

G is the gravitational constant

$M=8.7\cdot 10^{13}kg$ is the mass of the asteroid

m = 100 kg is the mass of the man

r = 2.0 km = 2000 m is the distance of the man from the centre of the asteroid

Substituting, we find

$F=(6.67\cdot 10^{-11}m^3 kg^{-1} s^{-2})\frac{(8.7\cdot 10^{13} kg)(110 kg)}{(2000 m)^2}=0.16 N$

2. 1.7 m/s

In order to stay in orbit just above the surface of the asteroid (so, at a distance r=2000 m from its centre), the gravitational force must be equal to the centripetal force

$m\frac{v^2}{r}=G\frac{Mm}{r^2}$