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3 years ago

Could someone help me ASAP !!

Mathematics

1 answer:

Lelechka [254]3 years ago

5 0

Answer:

LSA = 592cm^2.

Step-by-step explanation:

Well LSA is the SA but without the base so the blue square does not count.

So we have to find the area of the triangle which is b*h/2.

So 18.5*16 / 2 is 148.

And since there is 4 triangles with the same dimensions we do 148*4, 592cm^2.

You might be interested in

Suppose that each semester at a particular community college Manuel has to pay $1478 in tuition and $121 in fees.

Kamila [148]

Answer:

Step-by-step explanation:

Let x be time, in semesters, remaining before Manuel graduates. We find that Manuel's expenses are:

$1478/semester in tuition, and

$121/semester in fees

1. x semesters remaining: fees

Remaining cost for fees, y, is the product of the fee times the number of semesters, x:

y =($121/semester)*x

y = ($121)*x

2. x semesters remaining: tuition

Remaining cost, y, is the product of the tuition (times the number of semesters, x.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

3. x semesters remaining: tuition and fees

Remaining cost, y, is the sum of the products of the tuition (times the number of semesters, and the fees (tix.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

5 0

1 year ago

Please this is your answer.

xeze [42]

Answer:

3. 4

4. is correct

5. is correct

Step-by-step explanation:

3 is incorrect, you have to start with division first

3. 6-6/3

6-(6/3)

6-2

the answer for question 3 is 4

question 5 and question 4 are correct

6 0

3 years ago

Read 2 more answers

Please help!

erik [133]

For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3

1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 

1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 

1 + 9x + 36x^2 + 84x^3 

In my experience, up to the x^3 is often adequate to approximate a route. 

(1+x) = 0.98 

x = 0.98 - 1 = -0.02 

Substituting: 

1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 

approximation = 0.834 

Checking the real value in your calculator: 

(0.98)^9 = 0.834 

So you have approximated correctly. 

If you want to know how accurate your approximation is, write out the result of each in full: 

1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 

 (0.98)^9 = 0.8337477621 

So it is correct to 4

5 0

3 years ago

Read 2 more answers

the areas of two similar rectangles are 338 cm squared and 73 cm squared. what is the similarity ratio of the perimeters

Elena L [17]

The similarity ratio is 338 : 73.

You cannot simplify this ratio any further, since 73 is a prime number.

3 0

3 years ago

5x + 5 = x + 45 PLEASE HELP

Ostrovityanka [42]

$5x+5=x+45$

We'd rather not have x on both sides of the equation when trying to solve this. To eliminate the x on the right side, subtract both sides by x.

$5x+5-x=x+45-x$
$4x+5=45$

Let's get eliminate the "5" on the left side. Subtract both sides by 5.

$4x+5-5=45-5$
$4x=40$

To finish this, divide both sides by 4.

$4x \div 4=40 \div 4$
$x=10$

That is the answer. Hope this helps! :)

5 0

4 years ago