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Law Incorporation [45]
3 years ago
9

Hello Everyone Can I Get Some Help With This Work Needs To Be Shown.

Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

1.71875 or 1.7

Step-by-step explanation:

52 divided by 32 is 1.71875 then you round it to 1.7.

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The sum of two consecutive integers is 201 find the integers
telo118 [61]

100 and 101

the two integers are n and n+1. this means that 2n+1=201. n=100 and n+1=101

8 0
3 years ago
Read 2 more answers
Find the mean for the following sets of numbers.14,15,20,21
Jet001 [13]
The mean of those sets of numbers are 17.5
3 0
4 years ago
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The total bill for five people was $74.90. They Agreed to leave a 20% tip and divide the total cost evenly. How much did each of
Bingel [31]
TIP:
74.90*.2=14.98 
74.90+14.98=89.88
TOTAL:
89.88/5=17.98

each person pays $17.98

Hope this helps!
3 0
3 years ago
Express the recurring decimal 0.142 recurring as a fraction in its simplest form.
kupik [55]

Answer:

7/165

Step-by-step explanation:

We take number after the decimal point     042

then we subtract  the non repeating.In this case is 0 so we not subtract anything

This will be the numerator  42

For each repeating decimal we write a 9 (in this case 2 nines)

For each non repeating decimal we write a zero

Denominator is 990

42/990  =  7/165

7:165 = 0.0424242

I think this is what you do. Hope it helps!

5 0
3 years ago
In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the popu
olya-2409 [2.1K]

Answer:

19.6-2.42\frac{5.8}{\sqrt{42}}=17.43    

19.6+2.42\frac{5.8}{\sqrt{42}}=21.77    

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

\bar X= 19.6 represent the sample mean

\mu population mean

\sigma= 5.8 represent the population deviation

n=42 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.98 or 98%, the significance would be \alpha=0.02 and \alpha/2 =0.1, and the critical value would be t_{\alpha/2}=2.42

Replacing we got:

19.6-2.42\frac{5.8}{\sqrt{42}}=17.43    

19.6+2.42\frac{5.8}{\sqrt{42}}=21.77    

And the best option for this case would be:

a. (17.5, 21.7)

8 0
3 years ago
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