A=g≈-32
v=⌠a dt since a≈-32
v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s
v=-32t+20
h=⌠v dt
h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height? How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P
h=-16t^2+20t+3
Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:
h(t)=-16t^2+20t+hi, where hi is the initial height in feet.
This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)
If y is directly proportional to x then y:x.
When y = 30, x = 6 then 30/6 = 5:1. Therefor for every 1x there is 5y vice versa. When x = 12, then y = 5 * 12 = 60.
Therefore y = 60 hence 60:12
Divide 42 by 4 for one fourth. Divide 13.5 by 5 and multiply that by 2.
Volume of a Cone. The volume of a cone is 1 3 π r 2 h \frac { 1 } { 3 } \pi r ^{ 2 } h 31πr2h, where r denotes the radius of the base of the cone, and h denotes the height of the cone.
Your distance(d) is 1,814.4
1814.4 m = 5.6t square
then you square root 5.6t
the square root eliminates the square
you square root 1,814.4 m
(I rounded 42.6) then divide 42.6 by 5.6
(I rounded 7.6)
