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inysia [295]
3 years ago
5

Write the sum using summation notation, assuming the suggested pattern continues.100 + 121 + 144 + 169 + ... + n2 + ...

Mathematics
1 answer:
leva [86]3 years ago
7 0

Sigma_n=10 ^infinity n^2


It would be infinite.



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Here we're given
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(c) x ≥ 2
P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}
=P(2)+P(3)
=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}
=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}
=3(0.01)(0.9)+1(0.001)1
=0.027+0.001
=0.028


8 0
3 years ago
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