Ask question

Ask question

All categories

Salsk061 [2.6K]

3 years ago

13

What is the simplified form of the following expression?(x10)(x2) x8 x12 x20 x100

2 answers:

notka56 [123]3 years ago

6 0

I believe the answer would be x20. Between the two parentheses there's a multiplication symbol. So you would just pretend that the parentheses aren't there cause the variable(s) (x) is/are like terms. So you would just multiply 10 times 2 and put out the x back in front of it

iogann1982 [59]3 years ago

5 0

I think the answer would be x^12

You might be interested in

What is the first step needed to solve

Mama L [17]

Do u have a pic of the problem?

6 0

3 years ago

Read 2 more answers

2( 4x + 2) = 4x - 12(x-1)

aksik [14]

Answer:

$x=\frac{1}{2}$

Step-by-step explanation:

distribute 2 into (4x+2) and -12 into (x-1)

8x+4=4x-12x+12

combine like terms

8x+4=-8x+12

add -8x on both sides

8x+8x+4=12

16x+4=12

subtract 4 on both sides

16x=8

divide both sides by 16

x=1/2

hope this helps

8 0

3 years ago

On an assembly line, 1/5 of an item is made in 3/4 of an hour. What is the unit rate?

choli [55]

I don’t know if I’m wrong but Yeah I Think It’s C

3 0

3 years ago

What is the equation to find the Surface Area for a Cone?

defon

Answer:

A=πr(r+h2+r2)

Step-by-step explanation:

literally just search it up

4 0

2 years ago

Read 2 more answers

A small metal bar, whose initial temperature was 10° C, is dropped into a large container of boiling water. How long will it tak

IgorC [24]

Answer

According to newton law of cooling

$\dfrac{d T}{dt} = k (T - T_a)$

and

$T = Ce^{kt} + T_a$

now At Ta = 100

T₀ = 10 °C

T₁ = 12° C

$T(0) = Ce^{0} + T_a$

10 = C + 100

C = -90

now,

$12 = -90e^k + 100$

$e^k = \dfrac{88}{90}$

$k = ln{\dfrac{88}{90}}$

at time equal to t

T(t) = 70

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$70 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{3}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{3})$

t = 48.88 s

hence, after 48.88 s the temperature of the body will be 70°C

b) time taken to reach 98°C

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$98 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{45}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{45})$

t = 390 s

hence, after 390 s the temperature of the body will be 98°C

5 0

3 years ago