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notka56 [123]
3 years ago
8

SUPER ULTRA MEGA IMPORTANT QUESTION!!!! IF YOU CAN ANSWER THIS CORRECTLY I WILL GIVE YOU 100 POINTS BUT IF YOU DON'T ANSWER IT C

ORRECTLY YOU'LL GET A BIG REPORT. SO STAY AWARE AND HAVE A NICE DAY!

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

5x

Step-by-step explanation:

x = number of waffle cones the shop sells

cake cones = 5 times the number of waffle cones

cake cones = 5x

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HELP PLZ ASAP ITS DUE TOMORROW:(((( HELP
iVinArrow [24]

Answer:

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3 years ago
Julio drives to salem every 9 days and drives to Monmouth every 15 days. In how many days will he drive to both salem and Monmou
Helga [31]

Answer:

in  90 days

Step-by-step explanation:

you find the lcm of 9 and 15

6 0
3 years ago
Read 2 more answers
11/28+4/7 = simplest form
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The answer to this question is 27/28
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3 years ago
A random sample of of 100 voters in a town is selected, and 24 are found to support an annexation suit. Find the 96% confidence
lbvjy [14]

Answer: 0.24 +/- 0.088 = (0.152, 0.328)

Step-by-step explanation:

The point estimate p is given by;

p= 24/ 100 = 0.24

Z value for 96% confidence interval is 2.05

The solution for the given confidence interval is derived using the equation

p +/- z√(pq/n)

Where p = 0.24 q= 1-p = 0.76, n=100 z= 2.05

= 0.24 +/- 2.05√(0.24×0.76/100)

= 0.24 +/- 2.05(0.0427)

=0.24 +/- 0.088

= ( 0.152, 0.328)

6 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
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