Answer:
Hence average rate of change is greater for f(x) in (0,3).
Yes. f(x) is greater than g(x) in the interval (0,3)
Yes. g(3) <f(3)
Step-by-step explanation:
To find average rate of change of f and g in (0,3)
f(3)-f(0)/3 = (9-0)/3 =3
g(3) = -9-18 = -27
g(0) = 0
Rate of change in(0,3) of g(x) = -27/3 =-9
Hence average rate of change is greater for f(x) in (0,3)
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Both f and g have intercepts of y as 0
Hence both are equal.
3) Yes. f(x) is greater than g(x) in the interval (0,3)
Because g(x) <0 for all x in (0,3) while f(x) >0
4) g(3)= -9-18=-27 <f(3)
6.76 x 10^11
this is because when you are placing something in a scientific notation you basically move the decimal place behind the last hole number in this case 6. and count the remaining numbers behind the decimal such as .76,000,000,000 which there 11 counting 76 with the zeros. then you place the number of places behind the decimal as an exponent of 11 and keep all real numbers besides 0 as your other half
9514 1404 393
Answer:
x = -(9/7)n -81
Step-by-step explanation:
Subtract the n term.
x/-9 = 9 -n/-7
Multiply by -9.
x = -81 -(9/7)n
Answer:
consider x as the number of hours you work
so, the function that would satisfy this equation is
10x
Answer: 12x+18y ≤ 60
Step-by-step explanation:
Hi, to answer this question we have to write an inequality with the information given:
The product of the time that takes to do an oil change (12) and the number of oil changes(x); plus The product of the time that takes to do a tire change (18) and the number of tire changes; must be less or equal to 60 minutes (time available).
12x+18y ≤ 60
Feel free to ask for more if needed or if you did not understand something.
