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user100 [1]
3 years ago
12

You are taking a​ multiple-choice test that has 55 questions. each of the questions has 33 answer​ choices, with one correct ans

wer per question. if you select one of these choices for each question and leave nothing​ blank, in how many ways can you answer the​ questions
Mathematics
1 answer:
siniylev [52]3 years ago
5 0
<span>Each question has 5 possible choices for an answer>
1st question: 5 ways
2nd question: 5 ways
.......
12th question: 5 ways

----
Total # of possible answers 5*5*5...*5*5 = 5^12 = 244,140,625
-----
Cheers,
Stan H.
========================= 
The answer is 244,140,625</span>
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PLSSS HELPPP I WILL GIVE BRAINLIESTTTT!!!!!!!
Ksenya-84 [330]

Answer:

yes to both

Step-by-step explanation:

For a relationship to be a function then each value of x must relate to exactly one unique value of y.

This is the case in this table as

2 → 76

4 → 152

6 → 228

All unique values thus a function

To determine if it is linear then the rate of change is constant for each set of ordered pairs. This is measured using the slope formula.

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, 76) and (x₂, y₂ ) = (4, 152 ) ← ordered pair from table

m = \frac{152-76}{4-2} = \frac{76}{2} = 38

Repeat with (x₁, y₁ ) = (4, 152) and (x₂, y₂ ) = (6, 228)

m = \frac{228-152}{6-4} = \frac{76}{2} = 38

Since rate of change is constant then function is linear

8 0
2 years ago
A local hamburger shop sold a combined total of 649 hamburgers and cheeseburgers on Friday. There were 51 fewer cheeseburgers so
katrin2010 [14]

Answer: 350

Step-by-step explanation:

Let the cheeseburger be represented by a.

Since there were 51 fewer cheeseburgers sold than hamburgers. This means that hamburgers will be:

= a + 51.

Since the local hamburger shop sold a combined total of 649 hamburgers and cheeseburgers. This will be:

a + a + 51 = 649

2a + 51 = 649

2a = 649 - 51

2a = 598

a = 598/2

a = 299

299 cheeseburger were sold

Therefore, the number of hamburger sold will be:

= 649 - 299

= 350

7 0
2 years ago
!!!!!!!!!! 18 POINTS!!!!!!!!!!!
Gnoma [55]

Answer:

y=-3+4 or y=4-3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A gold, a silver, and a bronze medal are awarded in an Olympic event. In how many possible ways can the medals be awarded for a
RideAnS [48]

Answer:

720 possible ways

Step-by-step explanation:

The gold is awarded to the first position, the silver is awarded to the second position while the bronze is awarded to the third position.

The first position can be taken by any of the 10 runners

Now, the second position can be taken by remaining 9 runners

while the third position can be taken by the renaming 8 runners.

Thus, the number of ways in which these medals can be awarded = 10 * 9 * 8 = 720 ways

3 0
3 years ago
Does anyone know how to solve this?
Lilit [14]

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

4 0
3 years ago
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