Answer:
We can see that it is an isosceles triangle so base angles are equal.
Step-by-step explanation:
x + x + 56 = 180
2x = 180 - 56
2x = 124
x = 124/2
Therefore x = 62.
The axis of symmetry of f(x) is:
On a coordinate plane, a vertical dashed line at (2, 0) is parallel to
the y-axis ⇒ 2nd answer
Step-by-step explanation:
The vertex form of a quadratic function is f(x) = a(x - h)² + k, where
- (h , k) are the coordinates of its vertex point
- The axis of symmetry of it is a vertical line passes through (h , 0)
- The minimum value of the function is y = k at x = h
∵ f(x) = a(x - h)² + k
∵ f(x) = (x - 2)² + 1
∴ a = 1 , h = 2 , k = 1
∵ The axis of symmetry of f(x) is a vertical line passes through (h , 0)
∴ The axis of symmetry of f(x) is a vertical line passes through (2 , 0)
∵ Any vertical line is parallel to y-axis
∴ The axis of symmetry of f(x) is a vertical line parallel to y-axis and
passes through (2 , 0)
The axis of symmetry of f(x) is:
On a coordinate plane, a vertical dashed line at (2, 0) is parallel to
the y-axis
Learn more:
You can learn more about quadratic function in brainly.com/question/9390381
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We will have that for the previous year, he had in the account:

For the year previous to that one, he had:

For the previous year to that, he had:

For the year previous to that one, he had:

For the second year that the money was in the account, there was:

And the orinial ammount of money that was in the account was:

From this, we know that Jhon had originally $1400.37 in the bank account.
The answer is approximately 0.14