Here, DH = HF
x+3 = 3y
x = 3y-3 ----(I)
GH = HE
4x-5 = 2y+3
4x = 2y+8
Substitute value of x,
4(3y-3) = 2y+8
12y-12 = 2y+8
12y-2y = 12+8
10y = 20
y = 2
Now, substitute it in equation 1,
x = 3(2)-3
x = 6-3 = 3
So, your final answer is x=3 & y=2
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