Answer:
A sample size of 385 is needed.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 1.96.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
You feel that a reasonable estimate of the standard deviation is 10.0 hours.
This means that 
What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?
A sample size of n is needed. n is found when M = 1. So
Rounding up:
A sample size of 385 is needed.
I think the answer is 1.First, find the least common denominator, which is 6. Then, multiply the numerator and denominator by the same number to get 6 as the denominator.
is multiplied by 6 to get
.
is multiplied by 3 to get
.
is multiplied by 6 to get
. Since
is closest to
, 1 is the answer. Hope this helps!
Try YouTube there should be videos on how to do it .
What's the correlation coefficient of this date . 10,11,16,9,7,15,16,10,96,51,62,58,89,81,46,51
dem82 [27]
Assuming the question is in the wrong format and"date" is data.
I chose X= 10,11,16,9,7,15,16,10 and Y= <span>96,51,62,58,89,81,46,51
the correlation cooefficent is
-0.3351
</span>
1 people eat 3/8 pound of potato salad lets reoresent it：
x=3/8
Lets say n is the value of how many people ate with 7 people
7x=n
now substitute
7x=n
7(3/8)=n
21/8=n
n=2 5/8
